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Multiply the numerator on the left-hand side by the denominator on the right-hand side, and the denominator on the left-hand side by the numerator on the right-hand side.
4
We will solve the given equation and then check the solutions. 2x+4/x-3=3x/x-3 Let's do these two things one at a time!
We will solve the rational equation by using the Cross Products Property. If a numerator or denominator contains addition or subtraction, be sure to treat each one as a parenthetical factor in the cross multiplication process.
Cross multiply
Distribute (x-3)
LHS-2x^2=RHS-2x^2
Add terms
LHS+2x=RHS+2x
LHS+12=RHS+12
Rearrange equation
We obtained a quadratic equation. Let's identify the values of a, b, and c. x^2-7x+12=0 ⇕ 1x^2+( - 7)x+ 12=0 We see that a = 1, b = - 7, and c = 12. Next, we will substitute these values into the Quadratic Formula.
Substitute values
- (- a)=a
(- a)^2=a^2
Identity Property of Multiplication
Multiply
Subtract term
Calculate root
We will find the values for x by using the positive and the negative signs.
| x=7± 1/2 | |
|---|---|
| x=7+ 1/2 | x=7- 1/2 |
| x=8/2 | x=6/2 |
| x=4 | x=3 |
We found that x=4 and x=3 are possible solutions. Now we have to check them!
We check our solutions to see whether any of them are extraneous. To do so, we will substitute x=4 and x=3 into the given equation. Let's start with x=4.
Since we obtained a true statement, x=4 is a solution of the equation. Let's now substitute x=3 into the equation.
Note that a fraction with denominator equal to 0 is undefined, so we did not obtain a true statement. Therefore, x=3 is an extraneous solution.