The diagonals in a square are congruent, and they bisect each other.
No, see solution.
Practice makes perfect
Let's begin with recalling that, since a square is a rhombus, it has diagonals that are congruent and that bisect each other. This means that the distance between the third and the first base is the same as the distance between the second base and home.
Therefore, we can find the distance between the infield's center and home plate by dividing the diagonal by two. Let's start with converting the length of this diagonal into inches. To do this, let's multiply 127 by 12 as one foot is 12 inches.
127ft=127* 12in.= 1524in.
127ft3 38in.= 1524+3 38in.=1527 38in.
Now we can divide the diagonal length by 2.
Next, we will go back to feet and inches notation. To do this, let's rewrite the above result as a sum of two terms. One term should be divisible by 12.
The distance from each vertex of this square to the infield's center is 63 ft 7 1116 inches. We are given that the distance between the pitcher's mound and the home plate is 60 ft 6 inches. Since this distance is not equal to the half of the diagonal we evaluated above, the pitcher's mound is not located in the center of the infield.
