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McGraw Hill Integrated II, 2012

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McGraw Hill Integrated II, 2012 View details

5. Parts of Similar Triangles

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Exercise 48 Page 590

Use the Distance Formula.

sqrt(80) ≈ 8.9

Practice makes perfect

To determine the distance between two points, we use the Distance Formula. The coordinates of the given points are C(- 2,0) and D(6,4).

CD = sqrt((x_2-x_1)^2 + (y_2-y_1)^2)

SubstitutePoints

Substitute ( - 2,0) & ( 6,4)

CD=sqrt(( 6-( - 2))^2+( 4- 0)^2)

a-(- b)=a+b

CD=sqrt((6+2)^2+(4-0)^2)

Add and subtract terms

CD=sqrt(8^2+4^2)

Calculate power

CD=sqrt(64+16)

Add terms

CD=sqrt(80)

Calculate root

CD ≈ 8.9

The distance between C and D is approximately 8.9.

Subchapter links

Exercises p.586-590