5. Parts of Similar Triangles
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Apply the Triangle Midsegment Theorem twice and use the Parallelogram Opposite Angles Theorem.
Statements
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Reasons
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1. ∠H a right angle, L, K, and M are midpoints
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1. Given
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2. KL and KM are midsegments of â–³ GHJ
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2. Definition of midsegment
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3. KL∥ JH and KM∥ GH
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3. Triangle Midsegment Theorem
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4. KLHM is a parallelogram
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4. Definition of parallelogram
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5. ∠H ≅ ∠LKM
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5. Parallelogram Opposite Angles Theorem
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6. ∠LKM is a right angle
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6. Definition of congruent angles
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Let's consider the right triangle â–³ GHJ where K, L, and M are the midpoints of each sides.
Notice that both KL and KM are midsegments of â–³ GHJ. We can apply the Triangle Midsegment Theorem.
| Triangle Midsegment Theorem | |
|---|---|
| â–³ GHJ and KL | â–³ GHJ and KM |
| KL ∥ JH | KM ∥ GH |
From the above we get that KLHM is a parallelogram.
Then, by the Parallelogram Opposite Angles Theorem we conclude that ∠H ≅ ∠LKM. Since ∠H is a right angle we get that ∠LKM is a right angle as well, and this is what we wanted to prove.
Given: & ∠H a right angle & L, K, and M are midpoints Prove: & ∠LKM is a right angle We will summarize the proof we did above in the following two-column table.
Statements
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Reasons
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1. ∠H a right angle, L, K, and M are midpoints
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1. Given
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2. KL and KM are midsegments of â–³ GHJ
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2. Definition of midsegment
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3. KL∥ JH and KM∥ GH
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3. Triangle Midsegment Theorem
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4. KLHM is a parallelogram
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4. Definition of parallelogram
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5. ∠H ≅ ∠LKM
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5. Parallelogram Opposite Angles Theorem
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6. ∠LKM is a right angle
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6. Definition of congruent angles
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