McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
5. Parts of Similar Triangles
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Exercise 45 Page 590

See solution.

Practice makes perfect
We are asked to prove that △ EFG is congruent to △ HFG if we know that EF≅HF and that G is the midpoint of EH. Since a midpoint divides a segment into two congruent segments, HG and GE are congruent.

By the Reflexive Property, we know that FG≅FG. Therefore, △ EFG has all three sides that are congruent to the sides of △ HFG. This means that these triangles are congruent by the Side-Side-Side Congruence Theorem.