McGraw Hill Integrated II, 2012
MH
McGraw Hill Integrated II, 2012 View details
5. Parts of Similar Triangles
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Exercise 10 Page 587

Recall that if two triangles are similar, the lengths of corresponding altitudes are proportional to the lengths of corresponding sides.

≈77 ft

Practice makes perfect
Let's begin with recalling one of the Special Segments of Similar Triangles Theorems. If two triangles are similar, the lengths of corresponding altitudes are proportional to the lengths of corresponding sides. Now, let's look at the given diagram. Let x be the distance between the intersection of the roads and the bank.
We can create a proportion using the fact that the lengths of corresponding altitudes are proportional to the lengths of corresponding sides. x/50=382/248 Now, we will solve the proportion for x using cross multiplication.
x/50=382/248
x*248=50*382
248x=19100
x=19100/248
x=77.01612...
x≈ 77
The bank is approximately 77 feet from the intersection of the roads.