McGraw Hill Integrated II, 2012
MH
McGraw Hill Integrated II, 2012 View details
5. Parts of Similar Triangles
Continue to next subchapter

Exercise 50 Page 590

sqrt(232) ≈ 15.2

Practice makes perfect

To determine the distance between two points, we use the Distance Formula. The coordinates of the given points are J(- 4,- 5) and K(2,9).

JK = sqrt((x_2-x_1)^2 + (y_2-y_1)^2)
JK=sqrt(( 2-( - 4))^2+( 9-( - 5))^2)
JK=sqrt((2+4)^2+(9+5)^2)
JK=sqrt(6^2+14^2)
JK=sqrt(36+196)
JK=sqrt(232)
JK ≈ 15.2

The distance between J and K is approximately 15.2.