McGraw Hill Integrated II, 2012
MH
McGraw Hill Integrated II, 2012 View details
5. Parts of Similar Triangles
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Exercise 7 Page 587

If two triangles are similar, then the lengths of their corresponding altitudes are proportional to the lengths of their corresponding sides.

8.5

Practice makes perfect

Let's analyze the given triangles.

First, let's notice that two angles of the bigger triangle are congruent to two angles of the smaller triangle. Therefore, we can say that these triangles are similar by the AA Similarity Theorem. △_(Bigger) ~ △_(Smaller) Now, we are given the lengths of the altitudes of the triangles. Recall that if two triangles are similar, the lengths of their corresponding altitudes are proportional to the lengths of their corresponding sides. Using this fact, we can write the following proportion. 7.5/15 = x/17 Let's solve it for x using inverse operations.
7.5/15 = x/17
Solve for x
1/2 = x/17
17 * 1/2=x
8.5=x
x=8.5
We found that the value of x is 8.5.

Extra

Special Segments of Similar Triangles

In similar triangles we have some special segments that have lengths proportional to the lengths of corresponding sides. Let's list them!

Using this information we can write several proportions for any two similar triangles.