McGraw Hill Integrated II, 2012
MH
McGraw Hill Integrated II, 2012 View details
5. Parts of Similar Triangles
Continue to next subchapter

Exercise 37 Page 590

If two triangles are similar, then the lengths of their corresponding altitudes are proportional to the lengths of their corresponding sides.

2.2

Practice makes perfect

Let's look at the given triangles.

Recall that if two triangles are similar, the lengths of their corresponding altitudes are proportional to the lengths of their corresponding sides. Therefore, we can write the following proportion. AB/3.15 = 4.4/6.3 Let's solve it!
AB/3.15 = 4.4/6.3
â–Ľ
Solve for AB
6.3AB=(3.15)(4.4)
6.3AB=13.86
AB = 2.2