McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
4. Parallel Lines and Proportional Parts
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Exercise 60 Page 581

Notice that △ OMK is similar to △ POK by AA Similarity Theorem.

13.5 ft

Practice makes perfect

We are asked to find the distance across the stream using the fact that Mr. Turner uses a carpenter's square to do this.

Let's notice that the sum of the measures of ∠ MOK and ∠ KOP is equal to 90^(∘), as together they form a right angle. m∠ MOK+m∠ KOP=90^(∘) ⇓ m∠ MOK = 90^(∘)-m∠ KOPNext, recall that the sum of all angle measures in each triangle is equal to 180^(∘). Using this, we can write an equation for △ OMK. Then we will substitute the values we know.
m∠ MOK+m∠ OKM+m∠ KMO=180^(∘)
90^(∘)-m∠ KOP+m∠ OKM+m∠ KMO=180^(∘)
90^(∘)-m∠ KOP+ 90^(∘)+m∠ KMO=180^(∘)
Simplify
180^(∘)-m∠ KOP+m∠ KMO=180^(∘)
180^(∘)+m∠ KMO=180^(∘)+m∠ KOP
m∠ KMO=m∠ KOP
We found that ∠ KMO and ∠ KOP are congruent.
Since △ OMK and △ POK are right triangles and they have one more congruent angle, they are similar by Angle-Angle Similarity Theorem. Let's recall that in similar triangles corresponding sides are proportional. With this information, we can write the ratio. MK/OK=OK/KP We are given that MK is 1.5 ft and OK is 4.5 ft. Therefore, to solve for KP we will substitute the given lengths into the above proportion.
MK/OK=OK/KP
1.5/4.5=4.5/KP
Solve for KP
1.5* KP=4.5*4.5
KP=4.5*4.5/1.5
KP=4.5*3
KP=13.5
The distance across the stream is 13.5 feet.

Alternative Solution

Solving using the Pythagorean Theorem
We are given that MK is 1.5 ft and OK is 4.5 ft. Since △ OMK is a right triangle, we can solve for MO using the Pythagorean Method.
MO^2= 1.5^2+ 4.5^2
Solve for MO
MO^2=2.25+20.25
MO^2=22.5
sqrt(MO^2)=sqrt(22.5)
MO=sqrt(22.5)
MO=4.7434...
MO≈4.74
The length of MO is approximately 4.74. Let's add this information to our picture.
Next, let's notice that △ POM and △ OKM are similar by the Angle-Angle Similarity Theorem, as they are both right triangles and they share ∠ M. Using this fact, we can create a proportion. MP/MO=MO/MK Let's substitute appropriate values and solve for MP.
MP/MO=MO/MK
MP/4.74=4.74/1.5
Solve for MP
MP=4.74/1.5*4.74
MP=22.4676/1.5
MP=14.9784
MP=15
The length of MP is approximately 15 feet.

Finally, we can evaluate the length of KP by subtracting the length of MK from the length of MP. KP=MP-MK KP=15- 1.5=13.5 The distance across the stream is 13.5 ft.