McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
4. Parallel Lines and Proportional Parts
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Exercise 39 Page 579

Use the Side-Angle-Side (SAS) Similarity Theorem to show that the pair of triangles formed are similar.

See solution.

Practice makes perfect

For the construction we have the following diagram.

Notice that from the above we obtain the following triangle.
As we can see, ∠ A is common for △ ABC and △ ADE. Additionally, the sides of △ ABC that include ∠ A are proportional to the sides of △ ADE that include ∠ A. AD/AB = 40/100 = 2/5 = 40/100 =AE/AC Therefore, △ ADE ~ △ ABC because of the Side-Angle-Side (SAS) Similarity Theorem. This allows us to write the following proportion. DE/BC = AD/AB = 2/5 [0.2cm] ⇕ DE = 2/5 BC We have proven that DE is two-fifths the length of BC.

Extra

Extra

The sector compass works because, as seen before, it constructs a pair of similar triangles whose scale factor depends on where the marks are drawn.