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Recall the Triangle Midsegment Theorem.
Graph:
Coordinates: (-4,4) and (-0.5,6)
Explanation: see solution.
Let's begin with drawing â–³ ABC using the given points.
Now, we will recall the Triangle Midsegment Theorem.
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Triangle Midsegment Theorem |
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A midsegment of a triangle is parallel to one side of the triangle, and its length is one half the length of that side |
This means that to find the midsegment of â–³ ABC we should find the midpoints of AB and AC. To do this, we will use the Midpoint Formula. The midpoint O between two points M(x_1,y_1) and N(x_2,y_2) has the following coordinates. O(x_1+x_2/2,y_1+y_2/2) Let's start with evaluating the midpoint of AB. To do this, let's substitute ( -8, 7) and ( 0,1) into the above formula.
Substitute values
Add terms
Calculate quotient
The midpoint of AB has coordinates of (-4,4). Now, we will do the same to evaluate the midpoint of AC. Let's substitute ( -8, 7) and ( 7,5) into the Midpoint Formula.
Substitute values
Add terms
Calculate quotient
The midpoint of AC has coordinates of (-0.5,6). Therefore, by the Triangle Midsegment Theorem, the coordinates of the midsegment of â–³ ABC that is parallel to BC are (-4,4) and (-0.5,6).