McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
4. Parallel Lines and Proportional Parts
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Exercise 42 Page 580

Graph:

Coordinates: (-4,4) and (-0.5,6)
Explanation: see solution.

Practice makes perfect

Let's begin with drawing △ ABC using the given points.

Now, we will recall the Triangle Midsegment Theorem.

Triangle Midsegment Theorem

A midsegment of a triangle is parallel to one side of the triangle, and its length is one half the length of that side

This means that to find the midsegment of △ ABC we should find the midpoints of AB and AC. To do this, we will use the Midpoint Formula. The midpoint O between two points M(x_1,y_1) and N(x_2,y_2) has the following coordinates. O(x_1+x_2/2,y_1+y_2/2) Let's start with evaluating the midpoint of AB. To do this, let's substitute ( -8, 7) and ( 0,1) into the above formula.
(x_1+x_2/2,y_1+y_2/2)
(-8+ 0/2,7+1/2)
(-8/2,8/2)
(-4,4)
The midpoint of AB has coordinates of (-4,4). Now, we will do the same to evaluate the midpoint of AC. Let's substitute ( -8, 7) and ( 7,5) into the Midpoint Formula.
(x_1+x_2/2,y_1+y_2/2)
(-8+ 7/2,7+5/2)
(-1/2,12/2)
(-0.5,6)
The midpoint of AC has coordinates of (-0.5,6). Therefore, by the Triangle Midsegment Theorem, the coordinates of the midsegment of △ ABC that is parallel to BC are (-4,4) and (-0.5,6).