McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
4. Parallel Lines and Proportional Parts
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Exercise 22 Page 578

891 ft

Practice makes perfect

We are given a part of the Charleston map. We want to find the distance from Smith Street to Logan Street along Beaufain Street. Let x be that distance. Now, let's take a look at the given map and label the vertices with consecutive letters.

Let's begin by recalling the Proportional Parts of Parallel Lines Theorem.

Proportional Parts of Parallel Lines Theorem

If three or more parallel lines intersect two transversals, then they cut off the transversals proportionally.

Since we are given that BE is parallel both to CD and AF, we can use the Proportional Parts of Parallel Lines Theorem and write a proportion. AB/BC=FE/ED Let's substitute the lengths of the segments into the proportion and solve for x. To do this, we will use the Cross Products Property.
AB/BC=FE/ED
x/778=839/733
x* 733=778*839
733x=652 742
x=890.507...
x≈891
The distance from Smith Street to Logan Street along Beaufain Street is approximately 891 feet.