McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
4. Parallel Lines and Proportional Parts
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Exercise 43 Page 580

Notice that EH is the midsegment of triangle ABC.

FG=8.75 ft, EH=17.5 ft, and DJ=26.25 ft.

Practice makes perfect

Since we are told that each piece of siding is a uniform width we can deduct that EH is a midsegment of a triangle ABC. Let's recall the Triangle Midsegment Theorem.

Triangle Midsegent Theorem

A midsegment of a triangle is parallel to one side of the triangle, and its length is one half the length of that side.

According to this theorem, the length of EH is one half of the length of AC, which is 35 ft.

EH=1/2* 35=17.5 The length of EH is 17.5 feet. To evaluate the length of FG, let's notice that this segment is a midsegment of â–ł EHB. This means that its length is one half the length of EH. FG=1/2* 17.5=8.75 The length of FG is 8.75 feet. We can see that â–ł BDJ has side lengths of three quarters of side lengths of â–ł ABC. Therefore, the length of DJ is three quarters of the length of AC, which is 35 ft. DJ=3/4* 35=26.25 The length of DJ is 26.25 feet.