McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
4. Parallel Lines and Proportional Parts
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Exercise 57 Page 581

Review the Triangle Similarity Theorems that can help you prove that two triangles are similar.

Similar Triangles: △ ABE ~ △ CDE
Measure: AB=6.25

Practice makes perfect

To prove that two triangles are similar we will use one of the Triangle Similarity Theorems. Then we will find the desired measure.

Similar Triangles

We want to identify the similar triangles in the given diagram.

Let's recall the Angle-Angle Similarity Theorem.

If two angles of one triangle are congruent to two angles of another triangle, then the triangles are similar.

Notice that ∠ A and ∠ C are congruent angles, and ∠ AEB and ∠ CED are also congruent angles. This means that two angles of △ ABE are congruent to two angles of △ CDE. Therefore, by the Angle-Angle Similarity Theorem, △ ABE and △ CDE are similar triangles. △ ABE ~ △ CDE

Finding the Measure

Using our similarity statement from above, we can identify two pairs of corresponding sides that will help us find the requested length. AB corresponds with CD EA corresponds with EC Recall that corresponding sides of similar figures will have proportional lengths. We are given expressions for the lengths of these sides, which we can use to write a proportion. AB/CD = EA/EC ⇓ x/10 = 5/8 Let's solve the above equation for x.
x/10=5/8
Solve for x
x=10* 5/8
x=10* 5/8
x=50/8
x=6.25
Since AB=x, by the Transitive Property of Equality we have found that AB=6.25.