McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
4. Parallel Lines and Proportional Parts
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Exercise 2 Page 577

24

Practice makes perfect

Let's analyze the given figure. Since we are given a triangle with a line that is parallel to one of its sides, we can use the Triangle Proportionality Theorem.

The lengths of the segments intercepted by the parallel line are proportional. Let's write a proportion using the expressions for the lengths of the segments. XN/NZ=XM/MY Since we are given the lengths of XM and XY, we can find the length of MY.
XM+MY=XY
2+MY= 10
MY=8
Now we can substitute all known lengths into our proportion. XN/NZ=XM/MY ⇕ 6/NZ=2/8 Finally, we will solve this equation for NZ.
6/NZ=2/8
â–Ľ
Solve for NZ
6=2/8NZ
48=2NZ
24=NZ
NZ=24