5. Factoring Quadratic Expressions With a Leading Coefficient of 1
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Chapter 7
5.
Factoring Quadratic Expressions With a Leading Coefficient of 1
This lesson delves into the process of factoring quadratic expressions, specifically those with a leading coefficient of 1. Through various examples and scenarios, such as determining the dimensions of a photo frame or the area of a trough, readers are guided on how to break down these expressions into products of binomials. The lesson emphasizes the importance of understanding the signs of the coefficients and how they influence the factoring process. With practical applications like determining the perimeter of a triangle or the area of a rectangular rug, the lesson bridges the gap between theoretical knowledge and real-world application, making the concept of factoring more relatable and understandable.
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Lesson Settings & Tools
| | 10 Theory slides |
| | 10 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
Factoring Quadratic Expressions With a Leading Coefficient of 1
Slide of 10
One way to analyze a quadratic expression is to factor it — writing it as the product of two binomials. In this lesson, quadratic expressions with a leading coefficient of 1 will be factored.
Catch-Up and Review
Here are a few recommended readings before getting started with this lesson.
Challenge
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Finding a Pair of Numbers
Discussion
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Factoring a Quadratic Trinomial With Leading Coefficient 1
A quadratic trinomial in the form x^2+bx+c can be factored as (x+p)(x+q) if there exist p and q such that p+q=b and pq=c.
x^2+bx+c = (x+p)(x+q)
Proof
Suppose that the sum of two numbers p and q is equal to b and their product is equal to c. p+q = b and p* q = c
To show x^2+bx+c = (x+p)(x+q), substitute the equivalent expressions for b and c.
Therefore, the quadratic trinomial and the product of the binomials are equal. x^2+bx+c = (x+p)(x+q)
x^2+bx+c
SubstituteExpressions
Substitute expressions
x^2+( p+q)x+ pq
▼
Factor
Distr
Distribute x
x^2+px+qx+pq
FactorOut
Factor out x
x(x+p)+qx+pq
FactorOut
Factor out q
x(x+p)+q(x+p)
FactorOut
Factor out x+p
(x+q)(x+p)
CommutativePropMult
Commutative Property of Multiplication
(x+p)(x+q)
As an example, the trinomial below will be factored.
x^2+7x+12
These three steps can be followed to factor it.
1
Analyze the Signs of b and c
expand_more For some p and q, the aim is to write the given trinomial as follows. x^2+7x+12 = (x+p)(x+q) To do so, the signs of b and c will be used to determine the signs of p and q. x^2+ 7x+ 12 Here, b= 7 and c= 12, so both b and c are positive.
- Since c is positive, the factors p and q must have the same sign so that p* q is positive.
- Since b is positive, both p and q must be positive so that p+q is positive.
2
Find the Pair of Factors of c That Has a Sum of b
expand_more It is known that b=7, c= 12 and that p and q are positive integers. Therefore, two positive factors of 12 whose sum is 7 need to be found. The positive factor pairs of 12 will be listed and the pair with a sum of 7 identified.
| Positive Factors of 12 | Sum |
|---|---|
| 1 and 12 | 1+12=13 |
| 2 and 6 | 2+6=8 |
| 3 and 4 | 3+4=7 |
As seen, the factor pair of 3 and 4 meet these requirements, so the values of p and q are 3 and 4.
3
Write in Factored Form
expand_more For the given trinomial, two integers with a sum of 7 and a product of 12 were found. x^2+7x+12 ⇒ lp=3 q=4 Therefore, the trinomial can be written as the product of the binomials x+3 and x+4. x^2+7x+12 = (x+3)(x+4)
Example
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Factoring x^2+bx+c When b>0 and c>0
It's a three-day weekend and Tearrik has the day off from school. He wants to use this time to make a present for his brother's birthday. He bought a nice frame and then chose a photo of the two of them. However, the photo does not fit in the frame, so Tearrik needs to edit it.
The editing program represents the area of the photo as x^2+13x+42 and its length as x+7. Help Tearrik answer the following questions.
a Write a binomial that represents the width of the photo.
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b Tearrik is considering making a new picture frame himself. He needs to know approximately how much material he would need to make the frame. Find the perimeter of the photo if it is 9 inches wide.
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Hint
a Start by factoring the given quadratic expression.
b Use the given information to find x. Then, use the formula for the perimeter of a rectangle.
Solution
a The given quadratic expression represents the area of the photo. Therefore, it should be equal to the product of its length x+7 and width.
A & = l * w & ⇓ x^2 + 13x+42 & = (x+7) w To find w, the trinomial must be factored. To do so, identify b and c, and determine the signs of p and q. x^2+ 13x+ 42 Here, b= 13 and c= 42, so both b and c are positive.
- Since c is positive, the factors p and q must have the same sign so that p* q is positive.
- Since b is positive, both p and q must be positive so that p+q is positive.
Two positive factors of 42 whose sum is 13 need to be found. Now, list the positive factor pairs of 42 and identify the pair with a sum of 13.
| Positive Factors of 42 | Sum |
|---|---|
| 1 and 42 | 1+42=43 |
| 2 and 21 | 2+21=23 |
| 3 and 14 | 3+14=17 |
| 6 and 7 | 6+7=13 |
As seen, the factor pair 6 and 7 satisfies the conditions, meaning that the values of p and q are 6 and 7. Therefore, the trinomial can be written as the product of the binomials x+7 and x+6. x^2+13x+42 = (x+7)(x+6) Since x+7 represents the length of the photo, the x+6 must represent the width of the photo.
b The width of the photo is given as 9 inches. Since the binomial x+6 represents the width of the photo, the value of x can be found.
P = 2 (w + l)
SubstituteII
w= 9, l= 10
P = 2 ( 9+ 10)
AddTerms
Add terms
P = 2 (19)
Multiply
Multiply
P= 38
Example
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Factoring x^2+bx+c When b>0 and c<0
Vincenzo is using the extra day off school to begin building a kennel for his dog. In order to use the garden area in the most effective way, he has to build it on a triangular base. He draws a plan of a right triangle whose hypotenuse is represented by the binomial x+7.
It is known that the trinomial x^2+3x-10 is twice the area of the triangle and that the length of BC is greater than the length of AB.
a What are the possible leg lengths of the triangle when x=10?
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b Write an expression for the perimeter of the triangle to find the amount of fencing Vincenzo will need.
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Hint
a The given trinomial is equal to the product of the leg lengths of the triangle. Factor the given quadratic trinomial.
b The perimeter of a triangle is the sum of all of its side lengths.
Solution
a Since the given trinomial is twice the area of the triangle, the trinomial is equal to the product of leg lengths.
x^2+3x-10 = 2 * AB * BC/2 To find AB and BC, the quadratic trinomial needs to be written as a product of two binomials. x^2+3x-10= (x+p)(x+q) Now identify b and c to get an idea about the signs of p and q. x^2+3x-10 ⇓ x^2+ 3x+( - 10) For this expression, b= 3 and c= - 10, so b is positive but c is negative.
- Since c is negative, the factors p and q must have opposite signs so that p* q is negative.
- Since b is positive, the factor with a greater absolute value must be positive.
As such, the factor pairs of - 10 where one factor is negative should be listed. Then, look for the pair with a sum of 3.
| Positive Factors of - 10 | Sum |
|---|---|
| - 1 and 10 | - 1 + 10= 9 |
| 1 and - 10 | 1+(- 10)=- 9 |
| - 2 and 5 | - 2+5=3 |
| 2 and - 5 | 2+(- 5)=- 3 |
The factors that satisfy the conditions are - 2 and 5. Therefore, the trinomial can be written as the product of the binomials x-2 and x+5. x^2+3x-10 = (x-2)(x+5) These two binomials represent the lengths of the legs. When x=10, the expressions will be 8 and 15. x-2 & x=10 8 x+5 & x=10 15 This means that the longer side is 15 and the shorter side is 8. Since BC is greater than AB, BC=15 and AB = 8.
b The binomials representing the lengths of the legs are x-2 and x+5. Additionally, x+7 represents the hypotenuse. To find the perimeter in terms of x, all these binomials should be added.
P & = (x-2) + (x+5) + (x+7) & = 3x + 10
Example
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Factoring x^2+bx+c When b<0 and c<0
Tadeo is using the extra day off school to catch up on homework. He is almost finished with his math homework but is stuck on one problem. He reviews the notes he wrote about factoring the given quadratic trinomial with a leading coefficient of 1.
Answer
Error: When |p| > |q|, q must be a positive integer and p must be a negative integer so that their sum is negative.
Factored Form: (x-15)(x+6)
Hint
Start by identifying the values of b and c for the given quadratic trinomial.
Solution
First, b and c will be identified. x^2-9x-90 ⇓ x^2+( - 9)x+( - 90) Here, b= - 9 and c= - 90, meaning that both b and c are negative.
- Since c is negative, the factors p and q must have opposite signs so that p* q is negative.
- Since b is negative, the factor with a greater absolute value must be negative so that their sum is negative.
Therefore, Tadeo's first point is correct. If it is assumed that |p| > |q|, then p should be negative. In other words, Tadeo's second point is incorrect.
The given trinomial can be factored using this information. To do so, the factor pairs of - 90 where one factor is negative and its absolute value is greater than the other factor are listed. Then, the pair with a sum of - 9 should be looked for.
| Factors of - 90 | Sum of Factors |
|---|---|
| - 90 and 1 | - 90+1=- 89 |
| - 45 and 2 | - 45 + 2 = - 43 |
| - 30 and 3 | - 30 + 3= - 27 |
| - 18 and 5 | - 18 + 5= - 13 |
| - 15 and 6 | - 15 + 6= - 9 |
The factors that satisfy the conditions are - 15 and 6, so the trinomial can be written as the product of the binomials x-15 and x+6. x^2-9x-90 = (x-15)(x+6)
Example
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Factoring x^2+bx+c When b<0 and c>0
An inter-class quiz game is being held at Davontay's school this weekend, and he is his class's champion. The quizmaster Paulina asks Davontay to write a quadratic trinomial and then factor it. The conversation between the quizmaster and Dovantoy is shown in the diagram.
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Solution
Davontay needs to write a quadratic trinomial in the form x^2+bx+c. It is also given that b is negative and c=60. x^2+bx+c ⇓ x^2 +bx+60 Since the above trinomial can be factored, the value of b should be the sum of the two factors, p and q, of 60. x^2+bx+60= (x+p)(x+q) Now, two facts can be inferred from this trinomial.
- Since c is positive, the factors p and q must have the same sign so that p* q is positive.
- Since b is negative, both p and q should be negative so that p+ q is negative.
Based on this information, only negative factor pairs of 60 need to be listed.
| Negative Factors of 60 |
|---|
| - 1 and - 60 |
| - 2 and - 30 |
| - 3 and - 20 |
| - 4 and - 15 |
| - 5 and - 12 |
| - 6 and - 10 |
The sum of the factors in each pair could be the value of b, so Davontay's concern is valid. There are six values for b. These values can be found as follows.
| Factors of 60 | Sum |
|---|---|
| - 1 and - 60 | - 1 + (- 60) = - 61 |
| - 2 and - 30 | - 2 + (- 30) = - 32 |
| - 3 and - 20 | - 3 + (- 20) = - 23 |
| - 4 and - 15 | - 4 + (- 15) = - 19 |
| - 5 and - 12 | - 5 + (- 12) = - 17 |
| - 6 and - 10 | - 6 + (- 10) = - 16 |
Of these possible values, - 16 is the greatest, which meets Paulina's hint. Finally, the trinomial can be written. x^2-16x+60 The factors - 6 and - 10 have a product of 60 and a sum of - 16. Therefore, the trinomial can be written as the product of the binomials x-6 and x-10. x^2-16x+60 = (x-6)(x-10)
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Practice Factoring Quadratic Trinomials
Factor each quadratic expression with a leading coefficient 1. Write the answer in such a way that the value of q is the greater factor.
Example
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Finding the Dimensions of a Trough by Factoring
Maya and her father spent the long weekend building a trough for the animals on their farm. Her father knows that Maya has a math test coming up soon, so he decides to help her prepare for it by quizzing her about the trough they just built.
The trough's length is 105 centimeters longer than its width. The area covered by the trough is 12 250 square centimeters.
b State if the solutions make sense. What are the width and length of the trough?
Answer
a Equation: w(w+105) = 12 250
Solutions: w=70 and w=- 175
Solutions: w=70 and w=- 175
b Only the positive solution makes sense because measures cannot be negative.
Width: 70 centimeters
Hint
a Use the formula for the area of a rectangle to write an equation.
b Length cannot be negative.
Solution
a The width of the trough is represented by w. Since the length of the rectangular trough is 105 centimeters longer than its width, w+105 represents the length.
External credits: Colin Smith
12 250 = w (w+105)
▼
Rewrite
Distr
Distribute w
12 250 = w^2+105w
SubEqn
LHS-12 250=RHS-12 250
0 = w^2 +105w -12 250
RearrangeEqn
Rearrange equation
w^2 +105w -12 250 =0
| Factors of - 12 250 | Sum of Factors |
|---|---|
| 1225 and - 10 | 1225 + (- 10)=1215 |
| 490 and - 25 | 490 + (- 25)= 465 |
| 350 and - 35 | 350 + (- 35)= 315 |
| 245 and - 50 | 245 + (- 50)= 195 |
| 175 and - 70 | 175 + (- 70)= 105 |
(w-70)(w+175) = 0
ZeroProdProp
Use the Zero Product Property
lcw-70=0 & (I) w+175=0 & (II)
AddEqn
(I): LHS+70=RHS+70
lw=70 w+175=0
SubEqn
(II): LHS-175=RHS-175
lw=70 w=- 175
b Recall the solutions of the equation written in Part A.
w = 70 and w=- 175 Since w represents a length, it cannot be negative. This means that only the positive value makes sense. The dimensions of the trough can be found by substituting w=75.
| Expression | w=75 | |
|---|---|---|
| Width | w | 75 |
| Length | w+105 | 75+105 = 175 |
The width of the trough is 70 centimeters and the length is 175 centimeters.
Closure
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Finding a Pair of Numbers
The challenge presented at the beginning can now be solved using the information covered in this lesson. Jordan wants to find a pair of integers with a sum of 11 and a product of 28.
p+q = 11 p * q = 28
Help Jordan find the pair of numbers.
Answer
4 and 7
Solution
The first step is to isolate q in the first equation. p + q =11 ⇒ q= 11-p
Now, the expression equivalent to q is substituted into the other equation. Then, the equation is rewritten so that a quadratic expression is formed on one side of the equation.
To solve this equation, the quadratic trinomial should be factored.
p^2 -11p +28
In this trinomial, b = - 11 and c=28. Since c is positive, factor pairs of 28 that have the same sign should be considered. Of those pairs, negative pairs are listed because b is negative.
p * q = 28
Substitute
q= 11-p
p * ( 11-p)= 28
▼
Rewrite
Distr
Distribute p
11p-p^2= 28
SubEqn
LHS-28=RHS-28
11p-p^2-28 = 0
MultEqn
LHS * (- 1)=RHS* (- 1)
- 11p + p^2 +28 = 0
CommutativePropAdd
Commutative Property of Addition
p^2 -11p +28 = 0
| Factors of 28 | Sum of Factors |
|---|---|
| - 28 and - 1 | - 28+ (- 1)=- 29 |
| - 14 and - 2 | - 14+ (- 2)=- 16 |
| - 7 and - 4 | - 7+ (- 4)=- 11 |
The factors - 7 and - 4 has a sum of - 11 and a product of 28. The trinomial can now be written as the product of the binomials p-7 and p-4. p^2 -11p +28 =0 ⇓ (p-7)(p-4) = 0 The left-hand side of the equation is a product of two factors. One of them must be zero so that the product is equal to zero. Therefore, p is either 7 or 4 by the Zero Product Property. (p-7)(p-4) = 0 ⇓ p =7 or p = 4 When p=7, q will be 4, as their sum is 11. Conversely, when p=4, q=7. Therefore, the numbers 7 and 4 are the numbers Jordan is looking for.
Factoring Quadratic Expressions With a Leading Coefficient of 1
Exercise 3.1
A skyscraper will be built on the plot of land shown in the diagram.
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To write an expression that represents the area of the plot of land, we will first divide the given diagram into two rectangles.
Recall that area of a rectangle can be found by multiplying its length by its width. Knowing this, we find the areas of the bottom and top rectangles.
| Length | Width | Area | |
|---|---|---|---|
| Bottom Rectangle | 35 | x | 35x |
| Top Rectangle | x | 25-x | x(25-x) |
Furthermore, the total area is the sum of the areas of the bottom and top rectangles. 35x+ x(25-x) Finally, we will simplify the above expression.
Given that the area of the land is 756 m^2, we can write an equation using the expression we found in Part A. 756=- x^2+60x Let's now rewrite it the equation.
Next, we will factor the quadratic trinomial on the left-hand side. x^2+( - 60)x+ 756 = 0 For this trinomial, b= - 60 and c= 756. Since the value of c is positive, only factor pairs of 756 that have the same sign will be considered. Since we want the sum of the factor pair to equal b and b is negative, both factors must be negative.
| Factors of 756 | Sum of Factors |
|---|---|
| - 3 and - 252 | 255 |
| - 6 and - 126 | - 132 |
| - 9 and - 84 | - 93 |
| - 12 and - 63 | - 75 |
| - 18 and - 42 | - 60 |
The factor pair - 18 and - 42 seems to match our requirements. We can now rewrite the quadratic expression in factored form. x^2-60x+756 = 0 ⇓ (x-18)(x-42) = 0 Finally, we will solve the equation by applying the Zero Product Property.
It seems like we have two possible values for x. However, recall that we determined the width of the top rectangle to be 25-x meters long. Since a measurement of length cannot be negative, this means that the value of x must be less than 25. Therefore, the only value of x that makes sense in this context is 18 meters.
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Factoring Quadratic Expressions With a Leading Coefficient of 1
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