McGraw Hill Glencoe Algebra 1, 2012
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McGraw Hill Glencoe Algebra 1, 2012 View details
1. Graphing Quadratic Functions
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Exercise 47 Page 550

Practice makes perfect
a For the quadratic function h(x)=ax^2+bx+c, the y-coordinate of the vertex is the maximum value of the function when a<0.

Let's identify the values of a, b, and c in the given quadratic function. y=- x^2-14x-16 ⇕ y= - 1x^2+( - 14)x+( - 16) We can see above that a= - 1, b= - 14, and c= - 16. We will now use these values to find the desired information. Since a= - 1 is less than 0, the parabola will open downwards. This means it will have a maximum value.

b The maximum value is given by substituting - b2a for x. Before we find the value of the function at this point, we need to substitute a= - 1 and b= - 14 in - b2a.
- b/2a
â–Ľ
Substitute values and evaluate
- - 14/2( - 1)
- - 14/- 2
- 14/2
- 7
Now we have to substitute - 7 for x in the given equation.
y=- x^2 -14x -16
y = -( - 7)^2 -14( - 7) -16
â–Ľ
Simplify right-hand side
y = - (49) -14(- 7) -16
y = - (49) +98 -16
y = - 49 +98 -16
y = 33
This tells us that the maximum value of the function is 33.
c Unless there are any specified restrictions on the x-values, the domain of a quadratic function is all real numbers. Therefore, the domain of this function is all real numbers. Furthermore, since a= - 1 is less than 0, the range is all values less than or equal to the maximum value, 33.

Domain:& {All real numbers} Range:& {y | y ≤ 33}