McGraw Hill Glencoe Algebra 1, 2012
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McGraw Hill Glencoe Algebra 1, 2012 View details
1. Graphing Quadratic Functions
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Exercise 46 Page 550

Practice makes perfect
a For the quadratic function h(x)=ax^2+bx+c, the y-coordinate of the vertex is the maximum value of the function when a<0.

Let's identify the values of a, b, and c in the given quadratic function. y=- 2x^2-16x+18 ⇕ y= - 2x^2+( - 16)x+ 18 We can see above that a= - 2, b= - 16, and c= 18. We will now use these values to find the desired information. Since a= - 2 is less than 0, the parabola will open downwards. This means it will have a maximum value.

b The maximum value is given by substituting - b2a for x. Before we find the value of the function at this point, we need to substitute a= - 2 and b= - 16 in - b2a.
- b/2a
â–Ľ
Substitute values and evaluate
- - 16/2( - 2)
- - 16/- 4
- 16/4
- 4
Now we have to substitute - 4 for x in the given equation.
y=- 2x^2 -16x +18
y = - 2( - 4)^2 -16( - 4) +18
â–Ľ
Simplify right-hand side
y = - 2(16) -16(- 4) +18
y = - 2(16) +64 +18
y = - 32 +64 +18
y = 50
This tells us that the maximum value of the function is 50.
c Unless there are any specified restrictions on the x-values, the domain of a quadratic function is all real numbers. Therefore, the domain of this function is all real numbers. Furthermore, since a= - 2 is less than 0, the range is all values less than or equal to the maximum value, 50.

Domain:& {All real numbers} Range:& {y | y ≤ 50}