McGraw Hill Glencoe Algebra 1, 2012
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McGraw Hill Glencoe Algebra 1, 2012 View details
1. Graphing Quadratic Functions
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Exercise 45 Page 550

Practice makes perfect
a For a quadratic function y=ax^2+bx+c, the y-coordinate of the vertex is the minimum value of the function when a>0.

Let's identify the values of a, b, and c in the given quadratic function. y=3x^2+18x-21 ⇕ f(x)= 3x^2+ 18x+( - 21) We can see above that a= 3, b= 18, and c= - 21. We will now use these values to find the desired information. Since a= 3 is greater than 0, the parabola will open upwards. This means it will have a minimum value.

b The minimum value is given by substituting - b2a for x. Before we find the value of the function at this point, we need to substitute a= 3 and b= 18 in - b2a.
- b/2a
â–Ľ
Substitute values and evaluate
- 18/2( 3)
- 18/6
- 3
Now we have to substitute - 3 for x in the given equation.
y = 3x^2+18x-21
y = 3( - 3)^2+18( - 3)-21
â–Ľ
Simplify right-hand side
y = 3(9)+18(- 3)-21
y = 3(9)-54-21
y = 27-54-21
y = - 48
This tells us that the minimum value of the function is - 48.
c Unless there are any specified restrictions on the x-values, the domain of a quadratic function is all real numbers. Therefore, the domain of this function is all real numbers. Furthermore, since a= 3 is greater than 0, the range is all values greater than or equal to the minimum value, - 48.

Domain:& {All real numbers} Range:& {y | y ≥ - 48}