McGraw Hill Glencoe Algebra 1, 2012
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McGraw Hill Glencoe Algebra 1, 2012 View details
1. Graphing Quadratic Functions
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Exercise 15 Page 549

Practice makes perfect
a For the quadratic function h(x)=ax^2+bx+c, the y-coordinate of the vertex is the maximum value of the function when a<0.

Let's identify the values of a, b, and c in the given quadratic function. y=- 3x^2+6x+3 ⇕ y= - 3x^2+ 6x+ 3 We can see above that a= - 3, b= 6, and c= 3. We will now use these values to find the desired information. Since a= - 3 is less than 0, the parabola will open downwards. This means it will have a maximum value.

b The maximum value is given by substituting - b2a for x. Before we find the value of the function at this point, we need to substitute a= - 3 and b= 6 in - b2a.
- b/2a
â–Ľ
Substitute values and evaluate
- 6/2( - 3)
- 6/- 6
6/6
1
Now we have to substitute 1 for x in the given equation.
y=- 3x^2 +6x +3
y = - 3( 1)^2 +6( 1) +3
â–Ľ
Simplify right-hand side
y = - 3(1) +6(1) +3
y = - 3 +6 +3
y = 6
This tells us that the maximum value of the function is 6.
c Unless there are any specified restrictions on the x-values, the domain of a quadratic function is all real numbers. Therefore, the domain of this function is all real numbers. Furthermore, since a= - 3 is less than 0, the range is all values less than or equal to the maximum value, 6.

Domain:& {All real numbers} Range:& {y | y ≤ 6}