McGraw Hill Glencoe Algebra 1, 2012
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McGraw Hill Glencoe Algebra 1, 2012 View details
1. Graphing Quadratic Functions
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Exercise 64 Page 551

Practice makes perfect
a To write a function in standard form we need to arrange it by descending exponents in the form y=ax^2+bx+c. In this case, we first need to multiply the two binomials, then rearrange the terms.
R = (5+p)(150-10p)
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Simplify right-hand side
R = 150(5+p)-10p(5+p)
R = 750 + 150p -10p(5+p)
R = 750 + 150p - 50p-10p^2
R = 750 + 100p - 10p^2
R = -10p^2 + 100p + 750
b To find the maximum value of the function, we first need to find the axis of symmetry then use that value of p to find the vertex. In our function from Part A, R = -10p^2 + 100p + 750, a=-10 and b=100. Let's use those values in the formula for the axis of symmetry.
p= - b/2a
p = - 100/2( -10)
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Evaluate
p = - 100/-20
p = - (-5)
p=5
Now, let's substitute p=5 into our function to find the value of R.
R = -10p^2 + 100p + 750
R = -10(5)^2 + 100(5) + 750
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Solve for R
R = -10(25)+100(5)+750
R = -250 + 500 + 750
R = 1000
The vertex is at (5,1000). Therefore, the maximum value of the function is $1000.
c The vertex shows us both the maximum value of the function as well as the number of times the price should be increased by $1. Since 5 was the p-value of the vertex, we can add that to the original value of $5 per poinsettia to get the price of $10 per poinsettia for maximum revenue.