We will start by identifying the values of a, b, and c.
y=5x^2+ 20x+ 10We can see that a = 5, b = 20, and c = 10. Since the y-intercept is given by the value of c, we know that the y-intercept is 10. Let's now substitute a=5 and b=20 into - b2a to find the axis of symmetry.
The equation of the axis of symmetry is x=- 2.
To find the vertex of the parabola, we will need to think of y as a function of x, y=f(x). We can write the expression for the vertex by stating the x- and y-coordinates in terms of a and b.
Vertex: ( - b/2a, f(- b/2a ) )
When determining the axis of symmetry, we found that - b2a=- 2. Therefore, the x-coordinate of the vertex is - 2 and the y-coordinate is f(- 2). To find this value, substitute our x-coordinate for x in the given equation.
