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| 16 Theory slides |
| 10 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
Here are a few practice exercises before getting started with this lesson.
There are different scenarios where not all digits of a number are meaningful. In these cases, the number of decimal places required is usually given. However, there are cases where the number of decimal places needed can be deduced from the problem's context.
In any case, it is important to know how to round a number to a specific number of decimal places.
Rounding a decimal number to n decimal places means to rewrite the number in a simpler and shorter form with exactly n decimals. The final result will be an approximation to the given number.
The number 27.6495183 rounded to two decimal places is 27.65.
The following steps should be followed to round a number to n decimal places.
Consider the number 27.64951. In each column, the corresponding decimal place is highlighted.
Round to One Decimal Place | Round to Two Decimal Places | Round to Three Decimal Places |
---|---|---|
27. 64951 | 27.6 4951 | 27.64 951 |
Round to One Decimal Place | Round to Two Decimal Places | Round to Three Decimal Places |
---|---|---|
27. 6|4951 | 27.6 4|951 | 27.64 9|51 |
Round to One Decimal Place | Round to Two Decimal Places | Round to Three Decimal Places |
---|---|---|
27. 6| 4951 ↓ 27. 6| 4951 | 27.6 4| 951 ↓ 27.6 5| 951 | 27.64 9| 51 ↓ 27.6410| 51 ↓ 27.6 5 0| 51 |
The following table shows the results of rounding 27.64951 to one, two, and three decimal places.
Round to One Decimal Place | Round to Two Decimal Places | Round to Three Decimal Places |
---|---|---|
27.6 | 27.65 | 27.650 |
Mrs. Mathematiks asked Izabella to paint the Hubble Telescope on the classroom wall. Izabella thinks that she should draw a grid before doing the actual painting. She is told that squares with a side length of 7.374 centimeters will work well, but she only has this ruler.
Since the ruler only shows the measurements down to the tenth of a centimeter, round the original length to the tenth value, one decimal place.
The exact side length of the square Izabella wants to draw is given to the thousandth of a centimeter. Therefore, it has a precision of three decimal places.
Because the ruler measures to the tenth of a centimeter, Izabella cannot draw the square using the exact dimensions. To draw the square precisely, she must round the original length to a precise length that the ruler can measure.
The exact length must be rounded to one decimal place.
Next, apply the steps to round a decimal number.
In conclusion, Izabella should use a length of 7.4 centimeters to precisely draw the square's sides.
Izabella used a pencil to draw an outline of the previously measured square to make a grid layout of many squares. Doing this helped her paint the telescope accurately. The image shows how the grid helped her painting process.
Round the given number to the specified number of decimal places.
When announcing lottery results, an approximation of the winnings is generally used instead of listing the actual amount of money won.
In this case, the actual amount written in the title has been rounded to have only one significant figure. Rounding to significant figures is very similar to rounding to decimal places except for the final step.
Rounding a number to n significant figures means to rewrite the number so that it has exactly n significant figures. The result is an approximation of the number.
The number 6213.4983 rounded to three significant figures becomes 6.21* 10^3.
Consider the number 6213.4983. In each column, the corresponding significant figure is highlighted.
Round to Three Significant Figures | Round to Five Significant Figures | Round to Six Significant Figures |
---|---|---|
62 13.4983 | 6217. 3983 | 6217.3 983 |
Round to Three Significant Figures | Round to Five Significant Figures | Round to Six Significant Figures |
---|---|---|
62 1|3.4983 | 6213. 4|983 | 6213.4 9|83 |
Round to Three Significant Figures | Round to Five Significant Figures | Round to Six Significant Figures |
---|---|---|
62 1| 3.4983 ↓ 62 1| 3.4983 | 6213. 4| 983 ↓ 6213. 5| 983 | 6213.4 9| 83 ↓ 6213.410| 83 ↓ 6213. 5 0| 83 |
The following table shows the results of rounding 6203.4983 to 3, 5, and 6 significant figures.
Round to Three Significant Figures | Round to Five Significant Figures | Round to Six Significant Figures |
---|---|---|
62 1 3.4983 ↓ 6210 | 6213. 5 983 ↓ 6213.5 | 6213.5 0 83 ↓ 6213.50 |
It may happen that rounding a number results in an integer with fewer digits than the number of digits of the integer part of the original number. In this case, a bar is drawn above the last significant digit to indicate that there were more significant digits.
Rounding the Number 43 346 to | ||
---|---|---|
Two Significant Figures | Three Significant Figures | Four Significant Figures |
43 000 or 4.3* 10^4 | 43 300 or 4.33* 10^4 | 43 350 or 4.335* 10^4 |
Alternatively, writing the number using scientific notation helps identify the number of significant figures.
In the last rounding step, the numbers to the right of the second significant figure and the left of the decimal point must be replaced with zeros.
According to her boss, Paulina must round the number 21 392 to two significant figures. This can be done by following the steps below.
Paulina will announce on the radio that about 21 000 people have signed up for the marathon.
Round the given number to the specified number of significant figures.
When carrying out computations with significant figures, scientists usually use two different methods for rounding off a final answer. One method is used for addition and subtraction, while the other is used for multiplication and division.
Addition or Subtraction | Multiplication or Division |
---|---|
Round the result to the least number of decimal places in the numbers involved in the calculation. | Round the result to the least number of significant figures in the numbers involved in the calculation. |
The following table shows how to round the sum and the product of the numbers 34.78 and 156.294. Notice that the least number of decimal places is two and the least number of significant figures is four.
Computation | Rounded Result |
---|---|
34.78 + 156.294 = 191.074 | 191.07 (2 decimal places) |
34.78 * 156.294 = 5435.90532 | 5436 (4 significant figures) |
The words accuracy and precision play an important role when doing measurements and rounding. Accuracy refers to the closeness of the measurements to the exact, known, or acceptable value. Precision is the closeness of the measurements to each other.
The word precision is also used to indicate the number of decimal places of a number. Moreover, it can be used to determine which of two numbers is given with more detail.
The absolute error is the absolute value of the difference between a measured value and the exact value. The units of the absolute error correspond to the units of the measures. By definition, the absolute error is always greater than or equal to 0.
Absolute Error = |Measured Value- Exact Value|
Note that the absolute error gives only the distance between the measurements but does not say how significant the error is. For example, consider a professional basketball game. Suppose that the expected number of attendees was 28 000, but the actual number of people in attendance is 26 890. Absolute Error = |26 890 - 28 000| ⇓ Absolute Error = 1110 attendees
Here, the absolute error is 1110 attendees, but it is unknown whether this error is big or small.Eager to dish out another challenge, Mrs. Mathematikz gave Izabella, Paulina, and another friend Jordan the following problem.
The three friends solved the problem separately and came up with the following results. ccc Izabella &⟶& 15.6164 Paulina &⟶& 15.62 Jordan &⟶& 15.616 On Monday, Mrs. Mathematikz said that the value of the expression, rounded to three significant figures, is 15.6.
Result_(Izabella)= 15.6164, Exact= 15.6
Subtract terms
|0.0164|=0.0164
Absolute Error | |
---|---|
Izabella | |15.6164 - 15.6| = 0.0164 |
Paulina | |15.62-15.6| = 0.02 |
Jordan | |15.616-15.6| = 0.016 |
cccccc 0.016 &<& 0.0164 &<& 0.02 Jordan & & Izabella & & Paulina As determined, Jordan obtained the most accurate result.
The relative error is the ratio of the absolute error of a measurement to the exact value. The relative error tells how good a measurement is relative to the size of the object being measured. In other words, the relative error indicates how significant the absolute error is.
Relative Error =Absolute Error/Exact Value
The Relative Error Formula can be rewritten by substituting the Absolute Error Formula.
Relative Error =|Measured Value-Exact Value|/Exact Value
The percent error is the product between the relative error and 100 %. It represents the relative error as a percentage.
Percent Error = Relative Error * 100 %
Paulina did such a great job as a radio host that she is invited to announce another smaller race.
She notices something interesting about the runners at this smaller race — some are wearing headbands, and some are wearing sunglasses. She decides to take note of her observation to share it on the radio as a fun fact.
Headband | Sunglasses | |
---|---|---|
Number of Counted Runners With an Accessory | 26 | 111 |
Actual Number of Runners With an Accessory | 27 | 115 |
Measured Value= 26, Exact Value= 27
Subtract terms
|-1|=1
Measured Value= 111, Exact Value= 115
Subtract terms
|-4|=4
The Hubble Space Telescope is a telescope the size of a school bus that travels around Earth. Scientists and astronomers have learned a lot about space from Hubble's pictures of stars, planets, and galaxies.
After its launch in 1990, NASA found an error in the primary mirror that made the first few images appear blurrier than expected. It turned out that the curvature of the mirror was deflected by less than one-millionth of a meter — just one-fiftieth the width of a human hair! The following photo, taken in November 1993, shows the core of the galaxy M100.
NASA's first solution was to build replacement instruments — similar to a pair of prescription lenses — to fix the flaw. These repairs were done in December of 1993. The picture below, taken after the repairs, is the same galaxy shown in the first photo. What a difference!
This case shows that even though the error was a mere one-fiftieth of the width of a human hair, the final result was significantly impacted by the error.
Let's start by writing the full distance between the Earth and the Sun. 149.6 million km ⇓ 149 600 000 km Next, we have to convert this to meters. Note that 1 kilometer equals 1000 meters. With this information, we can write the following conversion factor. 1000 m/1 km If we multiply the distance by this conversion factor, we will get the distance in meters.
The next step is to round the previous number to two significant figures. To do that, we look at the digit that comes after the second significant figure. 14↓ 9 600 000 000 Since 9 is greater than 5, we increase the second significant figure by 1. Also, all numbers to the right of the significant figure will be replaced with zeros. Distance Rounded to Two Significant Figures [0.1cm] 150 000 000 000 m Finally, let's write this last number using scientific notation. 1.5* 10^(11) m ✓
Consider the following rectangle.
Paulina has likely rounded the longer length to 11 centimeters and the shorter length to 9 centimeters. These dimensions produce an area of 99 square centimeters. 11 * 9 = 99 cm^2 To minimize the rounding error, we should only round after the product has been calculated. That way, we only have to round one number instead of two, as Paulina did. Also, since 8.67 has the least number of significant figures, which is three, we want to round the area to three significant figures as well.
The rectangle's area is about 97.4 square centimeters.
We are rounding to two decimal places. Therefore, we need to look at the third decimal. 5.99↓ 51 Since the third decimal place is 5, we will increase the second decimal by 1. When doing so, the second decimal becomes 10, so we write 0 instead and add 1 to the next digit to the left. However, in this case, the first decimal also becomes 10. Again we write 0 instead and add one to the next digit to the left, this time the units digit. 5.9951 ≈ 6 .0000 Although we got a whole number as a final answer, we will keep two zeros after the decimal point to indicate that we rounded to two decimal places. 5.9951 ≈ 6.00
Again, we must look at the third decimal. 2.00↓ 21 Since the third decimal is less than 5, we will keep the second decimal the same. Again, we need to keep two decimals to indicate that we have rounded to two decimals. 2.0021 ≈ 2.00
We want to round the given number to four significant figures. We start by counting from the left until we reach the fourth significant figure. 1 8. 9 996 [-1.2em] First significant figure Second significant figure Third significant figure Fourth significant figure To round the number to four significant figures, we must consider the fifth digit. 18.99↓ 96 Because 9 is greater than 5, we increase the fourth digit by 1. The fourth digit then becomes 10, so we write 0 instead and add 1 to the third digit. However, in this case, the third digit also becomes 10. Again we write 0 instead and add one to the second digit. 18.9996 ≈ 19 .0000 Although we got a whole number as a final answer, we will keep two zeros after the decimal point to indicate that we rounded to four significant figures. 18.9996 ≈ 19.00