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| 12 Theory slides |
| 8 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
In the diagram's right triangles, some angle measures and side lengths are shown. Find the missing angle measures and lengths.
Consider the following table of trigonometric ratios for some acute angles.
sinθ | cosθ | |
---|---|---|
θ=15∘ | 0.258819… | 0.965925… |
θ=30∘ | 0.5 | 0.866025… |
θ=45∘ | 0.707106… | 0.707106… |
θ=60∘ | 0.866025… | 0.5 |
θ=75∘ | 0.965925… | 0.258819… |
The sine of an acute angle is equal to the cosine of its complementary angle. Similarly, the cosine of an acute angle is equal to the sine of its complementary angle.
By the Interior Angles Theorem, the sum of the interior angle measures of a triangle is 180∘. For a right triangle, since one angle measures 90∘, the other two angles are acute.
This is true for all pairs of complementary angles.
Write the given expression in terms of sine. Write your answer without the degree symbol.
The sine of an acute angle is equal to the cosine of its complement. Similarly, the cosine of an acute angle is equal to the sine of its complement.
Determine the value of x that makes the equation true.
Complementary angles add up to 90∘.
Substitute expressions
LHS−172x=RHS−172x
Commutative Property of Addition
Factor out x
Subtract fractions
LHS+171=RHS+171
Add fractions
b1⋅a=ba
LHS⋅17=RHS⋅17
Like the sine and cosine, the same relationship exists between the tangent and cotangent.
The tangent of an acute angle is equal to the cotangent of its complementary angle. Similarly, the cotangent of an acute angle is equal to the tangent of its complementary angle. Therefore, the following statements hold true.
Consider a right triangle with side lengths x, y, and z.
Use the tangent and cotangent relationship of complementary angles.
Consider the product of the first term and the last terms of the expression.
In physics, the phenomenon known as refraction of light is described as the change in a light's direction as it passes from one medium to another. Due to refraction, objects in the water may appear to be closer to the water's surface than they actually are. The diagram shows Ignacio's eye, from above the surface of the ocean, viewing a whale that looks to have an apparent depth of 30 feet below the surface of the ocean.
Use the tangent and cotangent relationship of complementary angles.
Begin by labeling points on the diagram.
The relationship discussed throughout this lesson can be extended to include the secant and cosecant ratios.
As may have already been noticed, three of the trigonometric ratios start with the prefixco.
codenotes that β is the co-angle, or complementary angle, of α. The identities seen in this lesson are referred to as cofunction identities.
Cofunction Identities | |
---|---|
sinθ=cos(90∘−θ) | cosθ=sin(90∘−θ) |
tanθ=cot(90∘−θ) | cotθ=tan(90∘−θ) |
secθ=csc(90∘−θ) | cscθ=sec(90∘−θ) |
Below we see △ABC.
In a right triangle, sine is the ratio of an acute angle's opposite side to the hypotenuse. sin θ = Opposite/Hypotenuse As a consequence of this ratio approaching 1, the opposite side of ∠ B would then increase. That then makes the difference between the hypotenuse and the opposite side smaller. Let's illustrate what happens to △ ABC as the opposite side of B increases.
Notice how the ratio approaches 1 as AC increases. This means that AC comes increasingly closer to BC. Therefore, we know that the first statement is true. i: AC≈ BC ✓ However, the quotient will never equal 1 since the hypotenuse is always greater than either of the legs in a right triangle. Therefore, the third statement must also be true. iii: AC < BC ✓ We also notice that ∠ B increases and ∠ C decreases as AC increases. This means m∠ B>m∠ C. When we examine the statements, we see that the second is true and the fourth is false. ii:& m∠ B > m∠ C ✓ iv:& m∠ C < m∠ B * For sin B to approach 1, the side opposite B needs to have a length close to that of the hypotenuse. That can only be the case if the opposite side is greater that the adjacent side. Now we know that the fifth statement is false and the sixth is true. v:& AB > AC * vi:& AC > AB ✓ We can now summarize that statements i, ii, iii, and vi are correct.