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| | 12 Theory slides |
| | 8 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
In the diagram's right triangles, some angle measures and side lengths are shown. Find the missing angle measures and lengths.
Consider the following table of trigonometric ratios for some acute angles.
| sin θ | cos θ | |
|---|---|---|
| θ = 15^(∘) | 0.258819 ... | 0.965925 ... |
| θ = 30^(∘) | 0.5 | 0.866025 ... |
| θ = 45^(∘) | 0.707106 ... | 0.707106 ... |
| θ = 60^(∘) | 0.866025 ... | 0.5 |
| θ = 75^(∘) | 0.965925 ... | 0.258819 ... |
As the measure of the angle increases, the sine ratio increases, and the cosine ratio decreases. Furthermore, some values are repeated. For example, the sine of 30^(∘) is the same as the cosine of 60^(∘), and the cosine of 75^(∘) is the same as the sine of 15^(∘). cllll sin 30^(∘) & = & cos 60^(∘) & = & 0.5 [0.8em] cos 75^(∘) & = & sin 15^(∘) & = & 0.258819... This relationship leads to a rule.
The sine of an acute angle is equal to the cosine of its complementary angle. Similarly, the cosine of an acute angle is equal to the sine of its complementary angle.
sin θ =cos(90^(∘) -θ) cos θ =sin(90^(∘) -θ)
By the Interior Angles Theorem, the sum of the interior angle measures of a triangle is 180^(∘). For a right triangle, since one angle measures 90^(∘), the other two angles are acute.
It follows that the sum of the measures of ∠ A and ∠ B is 90^(∘). Therefore, they are complementary angles. m∠ A + m∠ B =90^(∘) The sine and cosine ratios of complementary angles have a special relationship. To explore this, the three sides in the triangle will be labeled x, y, and z.
Using the definitions of sine and cosine, the following equations can be obtained. sin A=y/z & & cos A=x/z [1em] sin B=x/z & & cos B=y/z By the Transitive Property of Equality, it can be said that sin A=cos B and that cos A =sin B. sin A= y/z cos B= y/z ⇒ sin A = cos B [3em] cos A= x/z sin B= x/z ⇒ cos A= sin B
This is true for all pairs of complementary angles.
Write the given expression in terms of sine. Write your answer without the degree symbol.
The sine of an acute angle is equal to the cosine of its complement. Similarly, the cosine of an acute angle is equal to the sine of its complement.
θ= 27^(∘)
Subtract term
θ= 78^(∘)
Subtract term
Determine the value of x that makes the equation true.
Since the sine and cosine ratios relate side lengths of right triangles, these ratios can help identify some properties of right triangles. Magdalena is curious to determine if a right triangle exists where the sine and cosine of one of its acute angles have the same value. To do so, she lets x^(∘) be the measure of the angle and writes the following equation. sin x^(∘) = cos x^(∘) She is considering drawing a diagram and using the definitions of sine and cosine.
sin x^(∘)= BC/AC, cos x^(∘)= AB/AC
LHS * AC=RHS* AC
Substitute values
Let ∠ A and ∠ B be two acute angles of a right triangle. The sine of ∠ A and the cosine of ∠ B are expressed as follows. ∙ & sin A = 3/17x-1/17 [1.3em] ∙ & cos B = 2/17x+2/17 What is the value of x?
Complementary angles add up to 90^(∘).
Substitute expressions
LHS-2/17x=RHS-2/17x
Commutative Property of Addition
Factor out x
Subtract fractions
LHS+1/17=RHS+1/17
Add fractions
1/b* a = a/b
LHS * 17=RHS* 17
Like the sine and cosine, the same relationship exists between the tangent and cotangent.
The tangent of an acute angle is equal to the cotangent of its complementary angle. Similarly, the cotangent of an acute angle is equal to the tangent of its complementary angle. Therefore, the following statements hold true.
tan θ=cot(90^(∘) -θ) cot θ=tan(90^(∘) -θ)
Consider a right triangle with side lengths x, y, and z.
By using their definitions, the tangent and cotangent ratios can be written in terms of x and y. tan A = y/x & & cot A= x/y tan B= x/y & & cot B= y/x Since the acute angles of a right triangle are complementary, ∠ A and ∠ B are complementary angles. It can be seen that tan A=cot B and cot A=tan B. This is true for all pairs of complementary angles.
Use the tangent and cotangent relationship of complementary angles.
Consider the product of the first term and the last terms of the expression.
cot(θ) = 1/tan(θ)
tan 1^(∘) * a/tan 1^(∘)= a
In physics, the phenomenon known as refraction of light is described as the change in a light's direction as it passes from one medium to another. Due to refraction, objects in the water may appear to be closer to the water's surface than they actually are. The diagram shows Ignacio's eye, from above the surface of the ocean, viewing a whale that looks to have an apparent depth of 30 feet below the surface of the ocean.
Use the tangent and cotangent relationship of complementary angles.
Begin by labeling points on the diagram.
m∠ FDE= α, m∠ FDA= 90^(∘)
cot α= 1.73
LHS * 40=RHS* 40
Rearrange equation
Round to nearest integer
The relationship discussed throughout this lesson can be extended to include the secant and cosecant ratios.
As may have already been noticed, three of the trigonometric ratios start with the prefix co.
ccc
sine & cosine & tangent cosecant & secant & cotangent
Consider an example trigonometric equation.
sin α = cos β
In this case, the prefix co
denotes that β is the co-angle, or complementary angle, of α. The identities seen in this lesson are referred to as cofunction identities.
| Cofunction Identities | |
|---|---|
| sin θ = cos(90^(∘)-θ) | cos θ = sin(90^(∘)-θ) |
| tan θ = cot(90^(∘)-θ) | cot θ = tan(90^(∘)-θ) |
| sec θ = csc(90^(∘)-θ) | csc θ = sec(90^(∘)-θ) |
Consider the following triangle.
In the given right triangle, we know two angles. This means we can find the triangle's third angle by using the Interior Angles Theorem. m∠ θ+67^(∘) +90^(∘)= 180^(∘) ⇓ m∠ θ= 23^(∘) As we can see, the third angle has a measure of 23^(∘). Let's add this information to the diagram.
We want to know the value of sin 67^(∘). This is the ratio of the opposite leg to the hypotenuse. Using the information in the diagram, we can write an equation containing sin 67^(∘).
We can also write a second equation containing cos 23^(∘) by using the cosine ratio.
Since both sin 67^(∘) and cos 23^(∘) equals yx, we can equate these expressions and then use the information in the exercise about cos 23^(∘).
Consider △ ABC.
Examining the right triangle, we notice that ∠ A and ∠ C represent the acute angles of the triangle. Therefore, by the Interior Angles Theorem, the sum of their measures equals 90^(∘). m∠ A+m∠ C+90^(∘)=180^(∘) ⇓ m∠ A+m∠ C=90^(∘) Since the cosine of an acute angle equals the sine of the complement of the angle, we know that cos A must equal sin C. Therefore, we get the following equation. cos A&=sin C &⇓ 2x-11/2&=7/2-x Let's solve this equation for x.
From Part A, we know the value of x. Next, let's substitute its value into the expression for sin C.
By using the inverse of the sine ratio we can find the measure of ∠ C. sin C=1/2 ⇕ m∠ C=sin^(- 1)1/2=30^(∘) Let's add m∠ C and the length of BC to the diagram.
By using the tangent ratio we can now find AB.
As we can see, the length of AB is about 4 units.