Geo
Geometry View details
7. Properties of the Trigonometric Ratios
Continue to next lesson
Lesson
Exercises
Tests
Chapter 2
7. 

Properties of the Trigonometric Ratios

The sine and cosine of complementary angles share a unique bond. When exploring right triangles, it's evident that the sine of one acute angle is equivalent to the cosine of its complementary angle, and vice versa. This relationship is not just limited to sine and cosine; it extends to other trigonometric ratios like tangent and cotangent. Such relationships are pivotal in solving various mathematical problems, especially when dealing with angles and their complementary counterparts. Understanding these connections can be a powerful tool in the study of geometry and trigonometry, offering insights into the properties and behaviors of angles within triangles.
Show more expand_more
Problem Solving Reasoning and Communication Error Analysis Modeling Using Tools Precision Pattern Recognition
Lesson Settings & Tools
12 Theory slides
8 Exercises - Grade E - A
Each lesson is meant to take 1-2 classroom sessions
Properties of the Trigonometric Ratios
Slide of 12
In this lesson, the relationship between the sine and cosine of complementary angles will be investigated.

Catch-Up and Review

Explore

Investigating the Relationship Between Sine and Cosine

In the diagram's right triangles, some angle measures and side lengths are shown. Find the missing angle measures and lengths.

Three triangles with one common vertex
Use the information from diagram to complete the table of trigonometric ratios. Place the ratio into the appropriate cell.
Applet to fill in a table with sine and cosine ratios
Is there a recognizable pattern? If so, please describe it.
Discussion

Sine and Cosine of Complementary Angles

Consider the following table of trigonometric ratios for some acute angles.

sin θ cos θ
θ = 15^(∘) 0.258819 ... 0.965925 ...
θ = 30^(∘) 0.5 0.866025 ...
θ = 45^(∘) 0.707106 ... 0.707106 ...
θ = 60^(∘) 0.866025 ... 0.5
θ = 75^(∘) 0.965925 ... 0.258819 ...

As the measure of the angle increases, the sine ratio increases, and the cosine ratio decreases. Furthermore, some values are repeated. For example, the sine of 30^(∘) is the same as the cosine of 60^(∘), and the cosine of 75^(∘) is the same as the sine of 15^(∘). cllll sin 30^(∘) & = & cos 60^(∘) & = & 0.5 [0.8em] cos 75^(∘) & = & sin 15^(∘) & = & 0.258819... This relationship leads to a rule.

The sine of an acute angle is equal to the cosine of its complementary angle. Similarly, the cosine of an acute angle is equal to the sine of its complementary angle.


sin θ =cos(90^(∘) -θ) cos θ =sin(90^(∘) -θ)

Proof

By the Interior Angles Theorem, the sum of the interior angle measures of a triangle is 180^(∘). For a right triangle, since one angle measures 90^(∘), the other two angles are acute.

It follows that the sum of the measures of ∠ A and ∠ B is 90^(∘). Therefore, they are complementary angles. m∠ A + m∠ B =90^(∘) The sine and cosine ratios of complementary angles have a special relationship. To explore this, the three sides in the triangle will be labeled x, y, and z.

Using the definitions of sine and cosine, the following equations can be obtained. sin A=y/z & & cos A=x/z [1em] sin B=x/z & & cos B=y/z By the Transitive Property of Equality, it can be said that sin A=cos B and that cos A =sin B. sin A= y/z cos B= y/z ⇒ sin A = cos B [3em] cos A= x/z sin B= x/z ⇒ cos A= sin B

This is true for all pairs of complementary angles.

Example

Convert Between Sine and Cosine

Write the given expression in terms of cosine. Write your answer without the degree symbol.

Write the given expression in terms of sine. Write your answer without the degree symbol.

Hint

The sine of an acute angle is equal to the cosine of its complement. Similarly, the cosine of an acute angle is equal to the sine of its complement.

Solution

To write sin 27^(∘) in terms of cosine, the relationship between the sine and cosine of complementary angles will be used. Recall that complementary angles add up to 90^(∘). Therefore, to find the complement of 27^(∘), subtract the given angle from 90^(∘).
sin θ = cos(90^(∘) -θ)
sin 27^(∘) = cos(90^(∘)- 27^(∘))
sin27^(∘) = cos63^(∘)
Similarly, cos 78^(∘) can be written in terms of sine.
cos θ = sin(90^(∘) -θ)
cos 78^(∘) = sin(90^(∘)- 78^(∘))
cos 78^(∘) = sin 12^(∘)
Pop Quiz

Practice Converting Between Sine and Cosine

Determine the value of x that makes the equation true.

Example

Investigating Properties of Right Triangles

Since the sine and cosine ratios relate side lengths of right triangles, these ratios can help identify some properties of right triangles. Magdalena is curious to determine if a right triangle exists where the sine and cosine of one of its acute angles have the same value. To do so, she lets x^(∘) be the measure of the angle and writes the following equation. sin x^(∘) = cos x^(∘) She is considering drawing a diagram and using the definitions of sine and cosine.

a Use Magdalena's method to determine the type of the right triangle and the value of x.
b How can the sine and cosine of complementary angles be used to determine the value of x?

Answer

a Type of Right Triangle: Isosceles Right Triangle
Value of x: 45
b See solution.

Hint

a The sine of an acute angle is the ratio between the lengths of the opposite side and the hypotenuse. The cosine of an acute angle is the ratio between the lengths of the adjacent side and the hypotenuse.
b The complement of an angle that measures x^(∘) is 90^(∘)-x^(∘).

Solution

a Draw a right triangle with an acute angle that measures x^(∘).
The sine and cosine ratios of ∠ A can be written as follows. sin x^(∘) = BC/AC cos x^(∘) = AB/AC Since sin x^(∘) = cos x^(∘), the above values can be substituted into this equation.
sin x^(∘) = cos x^(∘)
BC/AC= AB/AC
BC=AB
It has been found that BC= AB. Therefore, △ ABC is an isosceles triangle. By the Isosceles Triangle Theorem, m ∠ A and m∠ C are equal to each other.
Since the sum of the interior angles of △ ABC is 180^(∘), the value of x, can be found.
m∠ A + m∠ B + m∠ C= 180^(∘)
x^(∘)+ 90^(∘) + x^(∘) = 180^(∘)
Solve for x^(∘)
2x^(∘) +90^(∘) = 180^(∘)
2x^(∘)= 90^(∘)
x^(∘) = 45^(∘)
This means that the value of x is 45.
b Recall that the cosine of any acute angle is equal to the sine of its complementary angle. Since the complement of an angle that measures x^(∘) is 90^(∘)-x^(∘), the equation below holds true. cos x^(∘) = sin(90^(∘)-x^(∘)) It is given that sin x^(∘) = cos x^(∘). By substituting sin(90^(∘)-x^(∘)) for cos x^(∘), the value of x can be found. sin x^(∘) = cos x^(∘) ⇕ sin x^(∘) = sin(90^(∘)-x^(∘)) For acute angles, the equation above is true when x^(∘) is equal to 90^(∘)-x^(∘).
x^(∘) = 90^(∘)-x^(∘)
2x^(∘) = 90^(∘)
x^(∘) = 45^(∘)
Therefore, the value of x is 45.
Example

Solving Problems Using the Relationship Between Sine and Cosine

Let ∠ A and ∠ B be two acute angles of a right triangle. The sine of ∠ A and the cosine of ∠ B are expressed as follows. ∙ & sin A = 3/17x-1/17 [1.3em] ∙ & cos B = 2/17x+2/17 What is the value of x?

Hint

Complementary angles add up to 90^(∘).

Solution

Notice that ∠ A and ∠ B are complementary angles because they are acute angles of a right triangle. m∠ A + m∠ B + 90^(∘) = 180^(∘) ⇕ m∠ B = 90^(∘)- m∠ A Using the relationship between sine and cosine of complementary angles, the following equation can be written. sin A = cos( 90^(∘) -A) ⇓ sin A = cos B Finally, in the above equation, the given expressions for sin A and cos B can be substituted. By doing so, the value of x can be found.
sin A = cos B
3/17x-1/17 = 2/17x+2/17
Solve for x
3/17x-1/17-2/17x = 2/17
3/17x-2/17x-1/17 = 2/17
(3/17-2/17)x-1/17 = 2/17
1/17x-1/17 = 2/17
1/17x = 2/17+1/17
1/17x = 3/17
x/17 = 3/17
x = 3
The value of x is 3.
Example

Using the Relationship Between Sine and Cosine to Solve Problems

In a right triangle, an acute angle measures w and satisfies the following equation. sin(w/4+20) = cos w Find the value of w.

Solution

Recall that the cosine of an acute angle is equal to the sine of its complementary angle. cos θ = sin(90^(∘) -θ) Since the complement of w is (90^(∘)-w), cos w is equal to sin(90^(∘)-w). sin(w/4+20) = cos(w) ⇕ sin(w/4+20) = sin(90-w) Because w is an acute angle, then ( w4+20) and (90-w) are also acute angles. Since the sines of these two angles are equal, the angles have the same measure.
w/4+20 = 90-w
Solve for w
w+w/4+20 = 90
4w/4+w/4+20 = 90
5w/4+20 = 90
5w/4 = 70
5w = 280
w=56
The value of w is 56.
Discussion

Tangent and Cotangent of Complementary Angles

Like the sine and cosine, the same relationship exists between the tangent and cotangent.

The tangent of an acute angle is equal to the cotangent of its complementary angle. Similarly, the cotangent of an acute angle is equal to the tangent of its complementary angle. Therefore, the following statements hold true.


tan θ=cot(90^(∘) -θ) cot θ=tan(90^(∘) -θ)

Proof

Consider a right triangle with side lengths x, y, and z.

right triangle

By using their definitions, the tangent and cotangent ratios can be written in terms of x and y. tan A = y/x & & cot A= x/y tan B= x/y & & cot B= y/x Since the acute angles of a right triangle are complementary, ∠ A and ∠ B are complementary angles. It can be seen that tan A=cot B and cot A=tan B. This is true for all pairs of complementary angles.

Example

Solving Problems Using the Relationship Between Tangent and Cotangent

Find the value of the following expression. tan1^(∘) * tan2^(∘) * tan3^(∘) * ... * tan89^(∘)

Hint

Use the tangent and cotangent relationship of complementary angles.

Solution

Consider the product of the first term and the last terms of the expression.

Since the complement of 89^(∘) is 1^(∘), by the tangent and cotangent relationship of complementary angles, it can be said that tan 89^(∘) is equal to cot 1^(∘).
tan 1^(∘) * tan 89^(∘)
tan 1^(∘) * cot 1^(∘)
Recall that the cotangent is the reciprocal of the tangent.
tan 1^(∘) * cot 1^(∘)

cot(θ) = 1/tan(θ)

tan 1^(∘) * 1/tan 1^(∘)
1
Therefore, the product of the first and the last terms is equal to 1. Similarly, the product of the second and second to last terms is equal to 1, and so on. The terms in this product can be grouped so that each pair has a product of 1. Since the given product has 89 terms, tan 45^(∘) will stand alone.
Note that tan 45^(∘) =1. Furthermore, the rest of the factors can be grouped by pairs such that their product is also 1. By the Identity Property of Multiplication, the value of the given expression is 1.
Example

Calculating Distances Using Trigonometry

In physics, the phenomenon known as refraction of light is described as the change in a light's direction as it passes from one medium to another. Due to refraction, objects in the water may appear to be closer to the water's surface than they actually are. The diagram shows Ignacio's eye, from above the surface of the ocean, viewing a whale that looks to have an apparent depth of 30 feet below the surface of the ocean.

External credits: @brgfx
If cot α = 0.75, and cot β = 1.73, calculate the distance between the apparent depth and actual depth of the whale. Round the answer to the nearest foot.

Hint

Use the tangent and cotangent relationship of complementary angles.

Solution

Begin by labeling points on the diagram.

External credits: @brgfx
Notice that B, D, and C are collinear. Therefore, the measures of ∠ FDE, ∠ FDA, and ∠ ADB add up to 180^(∘).
m∠ FDE + m∠ FDA+ m∠ ADB = 180^(∘)
α + 90^(∘)+ m∠ ADB = 180^(∘)
Solve for m∠ ADB
m∠ ADB = 180^(∘)-α-90^(∘)
m∠ ADB = 90^(∘)-α
This means that ∠ FDE and ∠ ADB are complementary angles. Consequently, the cotangent of α is equal to the tangent of its complementary angle. cot α = tan (90-α) From here, the distance between A and D can be calculated using tangent ratio of 90^(∘)-α. tan (90-α) = 30/AD ⇓ cot α = 30/AD Substitute the given value for cot α and solve for AD.
cot α = 30/AD
0.75 = 30/AD
Solve for AD
AD * 0.75 = 30
AD = 40
Now that AD is found, AC can be calculated. By the Alternate Interior Angles Theorem, β and ∠ ACD are congruent.
External credits: @brgfx
The cotangent ratio of β is then equal to AC40. Since cot β is known, AC can be found.
cot β = AC/40
1.73 = AC/40
Solve for AC
69.2 = AC
AC = 69.2
AC ≈ 69
The whale is located at a depth of about 69 feet. Therefore, Ignacio who is located at E sees the whale about 39 feet closer to the surface. AC- AB & = 69 -30 & = 39 What a cool phenomenon made sense by complementary angles!
Closure

Secant and Cosecant Ratios

The relationship discussed throughout this lesson can be extended to include the secant and cosecant ratios.

As may have already been noticed, three of the trigonometric ratios start with the prefix co. ccc sine & cosine & tangent cosecant & secant & cotangent Consider an example trigonometric equation. sin α = cos β In this case, the prefix co denotes that β is the co-angle, or complementary angle, of α. The identities seen in this lesson are referred to as cofunction identities.

Cofunction Identities
sin θ = cos(90^(∘)-θ) cos θ = sin(90^(∘)-θ)
tan θ = cot(90^(∘)-θ) cot θ = tan(90^(∘)-θ)
sec θ = csc(90^(∘)-θ) csc θ = sec(90^(∘)-θ)


Properties of the Trigonometric Ratios
Exercise 2.1
>
2
e
7
8
9
×
÷1
=
=
4
5
6
+
<
log
ln
log
1
2
3
()
sin
cos
tan
0
.
π
x
y