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The diagrams shows a transversal passing through a pair of parallel lines. By the Consecutive Interior Angles Theorem, if two parallel lines are cut by a transversal, the consecutive interior angles are supplementary angles. Since the angles measuring 7x-19^(∘) and 3x+14^(∘) are consecutive interior angles, they must be supplementary.
Add terms
LHS+5^(∘)=RHS+5^(∘)
.LHS /10.=.RHS /10.
To find y, let's notice that the angles measuring 5y-2^(∘) and 7x-19^(∘) are vertical angles.
These angles are congruent by the Vertical Angles Theorem. In other words, they have the same measure. 5y-2^(∘) = 7x-19^(∘) We previously found that x = 18.5^(∘). Let's substitute this value for x and solve the resulting equation for y.
x= 18.5^(∘)
Multiply
Subtract term
LHS+2^(∘)=RHS+2^(∘)
.LHS /5.=.RHS /5.
We know the length of two sides, 25 and 15, and that the measure of their included angle is 120^(∘). We can use substitute this information into the Law of Cosines to write an equation in terms of k.
Note that we only kept the principal root when solving the equation because k is the length of a side and lengths cannot be negative.