Core Connections Geometry, 2013
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Core Connections Geometry, 2013 View details
1. Section 7.1
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Exercise 8 Page 401

Diagram:

Width: 60mm
Area: 660mm^2

Practice makes perfect

We want to draw a diagram and find the width and area of the rectangle described in the exercise. Let's start by doing a rough sketch of this rectangle along with the given diagonal. Whether the scale and proportions are correct is not important now.

Since we are working with a rectangle, all of its internal angles are right angles. We know the lengths of both the diagonal and one side, so we can calculate the other missing dimension using the Pythagorean theorem.

From the exercise we know that a = 11 millimeters and c = 61 millimeters. Let's substitute these values into the equation and solve it for the side length b.

a^2+b^2=c^2
11^2+b^2 = 61^2
121+b^2 = 3721
b^2 = 3600
b = sqrt(3600)
b = 60

We found that the missing side length of the rectangle is 60 millimeters. Let's add this information to our sketch.

Lastly, we can use the following formula to find the area of the rectangle. A = l w Let's substitute 11 for the length l and 60 for the width w and multiply.

A = l w
A = 11( 60)
A = 660

The area of the rectangle is 660 square millimeters.