2. Section 2.2
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When solving a system of equations using substitution, there are three steps.
(II):y= 5x-2
(II):LHS-3x=RHS-3x
(II):LHS+2=RHS+2
(II): .LHS /2.=.RHS /2.
(I):x= 10
(I):Multiply
(I): Subtract term
Let's recall that there are three steps when solving a system of equations using substitution.
(II):y= x-4
(II):Distribute 3
(II):Add terms
(II):LHS+12=RHS+12
(II): .LHS /5.=.RHS /5.
(I):x= 29/5
(I):a = 5* a/5
(I): Subtract fractions