Core Connections Algebra 2, 2013
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Core Connections Algebra 2, 2013 View details
2. Section 2.2
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Exercise 116 Page 94

Practice makes perfect
a To find g( 12), we have to substitute x= 12 into g(x)=x^2-5 and evaluate.
g(x)=x^2-5
g( 1/2)=( 1/2)^2-5
g(1/2)=1^2/2^2-5
g(1/2)=1/4-5
g(1/2)=1/4-20/4
g(1/2)=-19/4
b Again to find g(h+1), we have to substitute x=h+1 into g(x)=x^2-5 and evaluate.
g(x)=x^2-5
g( h+1)=( h+1)^2-5
g(h+1)=h^2+2h+1-5
g(h+1)=h^2+2h-4