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See solution.
To find a second point, we can use the line's slope. A slope of 3 means that it will increase by 3 on the vertical axis for every 1 unit we travel in the positive horizontal direction.
The line through these points, have a y-intercept of (0,2) and a slope of 3.
y=mx+b In this equation, m is the line's slope and b is the y-intercept. We have m=3 and b=2. We can now write the equation of the line. y=3x+2
|c|c|c| n & 3n-1 & t(n) 1 & 3( 1)-1 & 2 2 & 3( 2)-1 & 5 3 & 3( 3)-1 & 8 4 & 3( 4)-1 & 11 Next, we will plot these points on one set of axes, and the line on the other.
Sequence:& {x | x= 1,2,3,4... } Function:& {x | x=All real numbers } Let's now look at their equations. Sequence:& t(n)=3n-1 Function:& y=3x+2 In both equations, the independent variable is multiplied by 3. In that respect they are similar.