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Consider the given equation.
$x_{2}+10x=-20 $
Let's start by solving it by completing the square. We see above that $b$ $=$ $10.$ Therefore, we need to start by adding $(210 )_{2}$ $=$ $25$ to both sides.
We found two solutions, $x=-5+5 $ and $x=-5−5 .$ Thus, we've showed that the equation can be solved by completing the square.

$x_{2}+10x=-20$

Solve for $x$

AddEqn$LHS+25=RHS+25$

$x_{2}+10x+25=5$

SplitIntoFactorsSplit into factors

$x_{2}+2x(5)+25=5$

WritePowWrite as a power

$x_{2}+2x(5)+5_{2}=5$

FacPosPerfectSquare$a_{2}+2ab+b_{2}=(a+b)_{2}$

$(x+5)_{2}=5$

RadicalEqn$LHS =RHS $

$x+5=±5 $

SubEqn$LHS−5=RHS−5$

$x=-5±5 $