Big Ideas Math Integrated I, 2016
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Big Ideas Math Integrated I, 2016 View details
2. Exponential Growth and Decay
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Exercise 30 Page 287

Determine if the value of the car can be modeled by an exponential growth function or not.

Error: The decay factor should be 0.86
Correction: About $11 761

Practice makes perfect

In the diagram, the value of a car in 2015 is calculated incorrectly.

To describe the error, we will first write a function modeling the value v(t) of the car after t year and then substitute 5 for t. We know that the value of a car decreases by 14 % annually, so we will use an exponential decay function. Therefore, the function v(t) is of the following form. v(t)= a(1- r)^t Here, a is the initial value and r is the rate of decay. In the question, the rate of decay is given as 14 %, or 0.14. The initial value of the car is 25 000. Then, the function becomes as follows. v(t)= 25 000(1- 0.14)^t ⇓ v(t)=25 000( 0.86)^t We see that the decay factor is equal to 0.86, not 1.14, as is written in the given solution. Correct: & v(t)=25 000( 0.86)^t ✓ Incorrect: & v(t)=25 000( 1.14)^t * To find the value of the car in 2015, we will substitute 5 for t.
v(t)=25 000(0.86)^t
b( 5)=25 000(0.86)^5
â–Ľ
Simplify right-hand side
v(5)=25 000(0.47042 ...)
v(5)=11 760.67544
v(5)=11 761
In 2015, the value of the car is about $11 761.