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| 12 Theory slides |
| 10 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
While watching a documentary about ancient civilizations, Ali wondered how scientists could determine the age of an object belonging to such ancient civilizations.
Ali recalled that his uncle, Mr. Jones, is an archaeologist! Ali called and asked him how are the ages of ancient objects determined.
Carbon-14 is a substance present in organisms that, once they expire, begin to be released from an object's body at a slow rate. To date an object this way consists of measuring the amount of carbon-14 in a sample and comparing it to known values of different ages.
Magdalena, excited for biology lab, is exploring about bacterial growth.
Time Elapsed, t | y=220t | Number of Bacteria, y |
---|---|---|
0 | 2200=1 | 1 |
20 | 22020=21 | 2 |
40 | 22040=22 | 4 |
60 | 22060=23 | 8 |
80 | 22080=24 | 16 |
Applications of exponential growth can also be encountered in the world of finance. Some people use the power of compound interest to grow their wealth exponentially.
Kriz, determined and focused, won an online video game competition. The first place prize was $1000!
Kriz decides to not spend the prize money. Instead, their parent suggests placing all of it into a Certificate of Deposit. This is a type of savings account with compound interest. The catch is that the money cannot be taken out for a certain period of time. Ngân Hàng, a local bank, offers a Certificate of Deposit with the interest rate at 3% compounded monthly.
compounded monthlyis that the interest is compounded each month of the year — meaning twelve times per year.
When the base of an exponential function is a number greater than 0 and less than 1, the function is said to be decreasing. In such cases, the function represents what is known as exponential decay.
Diego has saved for the past few years dreaming of buying a car with a drop top so he can cruise the streets looking fly. Diego runs to the nearest car dealer and is met by Mr. Peterson, a car salesmen. They come to an agreement where Diego trades in his old car to help pay for the new car.
Diego bought his car five years ago at the same dealer for $20000. Mr. Peterson states that the car depreciates at a rate of 15% annually.
Since the value of the car depreciates, the situation can be modeled using an exponential decay function.
t=5
Use a calculator
Round to 2 decimal place(s)
Select the option that best describes the table of values given below.
Exponential functions y=abt can model exponential decay as well as exponential growth. Identify the rate of decay or growth r for the indicated function. Write the corresponding rate in decimal form.
This lesson introduced the interesting concepts of compound interest, exponential growth, and exponential decay. Using the knowledge gained from this lesson, the introductory challenge can be modeled using an exponential decay function. Recall what the archaeologist had to say.
Find the decay factor of this situation.
Identify the rate of growth of the following exponential functions. Write your answer as a percentage.
Let's start by recalling the general form of exponential growth functions.
Exponential Growth |- y=a(1+r)^t
In this case a>0 is the initial amount and r>0 is the rate of growth written in decimal form. y=5(1+ 0.25)^t Our function represents exponential growth with a rate of growth of r= 0.25. To rewrite the rate of growth as a percentage, we move the decimal point 2 places to the right. r=0.25 ⇔ r=25 % Therefore, the rate of growth is 25 %.
Let's begin by rewriting the given function to match the exponential growth formula.
This time our function represents exponential growth with a rate of growth of r= 0.3. To rewrite the rate of growth as a percentage, we move the decimal point 2 places to the right. r=0.3 ⇔ r=30 % Therefore, the rate of growth is 30 %.
Let's begin by rewriting the given function to match the exponential growth formula.
This exponential growth function has a rate of growth of r= 0.8. To rewrite the rate of growth as a percentage, we move the decimal point 2 places to the right. r=0.8 ⇔ r=80 % Therefore, the rate of growth is 80 %.
Let's start by recalling the general form of exponential growth functions.
Exponential Growth |- y=a(1+r)^t
In this case a>0 is the initial amount and r>0 is the rate of growth written in decimal form. To write the function we first need to define the variables. Let y be the population, and let t be the number of years after the initial value. In this case the initial value is 500 000. a= 500 000 We are told that the population increases 8 % each year. This is the rate of growth. Let's write it as a decimal! r=8 % ⇔ r= 0.08 We now have enough information to write the requested function. Let's substitute our values into the general formula.
We can represent the given situation with the exponential function y=500 000(1.08)^t.
Identify the rate of decay of the following exponential functions. Write the rate of decay as a percentage.
Let's start by recalling the general form of exponential decay functions.
Exponential Decay |- y=a(1-r)^t
In this case a>0 is the initial amount and r>0 is the rate of decay written in decimal form. y=8.5(1- 0.15)^t Our function represents exponential decay with a rate of decay of r= 0.15. To rewrite the rate of decay as a percentage, we move the decimal point 2 places to the right. r=0.15 ⇔ r=15 % Therefore, the rate of decay is 15 %.
Let's begin by rewriting the given function to match the exponential decay formula.
This time our function represents exponential decay with a rate of decay of r= 0.03. To rewrite the rate of decay as a percentage, we move the decimal point 2 places to the right. r=0.03 ⇔ r=3 % Therefore, the rate of decay is 3 %.
Let's begin by rewriting the given function to match the exponential decay formula.
This exponential decay function has a rate of decay of r= 0.3. To rewrite the rate of decay as a percentage, we move the decimal point 2 places to the right. r=0.3 ⇔ r=30 % Therefore, the rate of decay is 30 %.
Let's start by recalling the general form of exponential decay functions.
Exponential Decay |- y=a(1-r)^t
In this case a>0 is the initial amount and r>0 is the rate of decay written in decimal form. To write the function, we first need to define the variables. Let y be the stock value, and let t be the number of years after the initial value. In this case the initial value is 200. a= 200 We are told that the stock decreases in value by 5 % each year. This is the rate of decay. Let's write it as a decimal! r=5 % ⇔ r= 0.05 We now have enough information to write the requested function. Let's substitute our values into the general formula.
We can represent the given situation with the function y=200(0.95)^t.
Ali, founder of Daytas sunglasses, plans to pay the salespeople a starting annual salary of $30000. The salary increases by 5% each year worked at the company. He wants keep track of their salaries over the years.
Let's start by recalling the general form of exponential growth functions.
Exponential Growth |- y=a(1+r)^t
In this case a>0 is the initial amount and r>0 is the rate of growth written in decimal form. To write the function, we first need to define the variables. Let y be the salary, and let t be the number of years that the employee has been working in the company. In this case the initial value is 30 000. a= 30 000 We are told that their salary increases 5 % each year. This is the rate of growth. Let's write it as a decimal! r=5 % ⇔ r= 0.05 We now have enough information to write the requested function.
We can find the employee's salary after 5 years of working in the company by evaluating the function we obtained in Part A at t=5. Let's do it!
The employee's annual salary will be about $38 288.45 after working in the company for 5 years. For helping, Ali has presented this pair of sunglasses. Great work!
The purchase price of this car is $20000. The value of the car depreciates by 8% for each year beginning from the date of purchase.
Let's start by recalling the general form of exponential decay functions.
Exponential Decay |- y=a(1-r)^t
In this case, a>0 is the initial amount and r>0 is the rate of decay written in decimal form. To write the function we first need to define the variables. Let y be the price of the car, and let t be the number of years that have passed since its purchase. In this case the initial value is 20 000. a= 20 000 We are told that the car depreciates 8 % each year. This is the rate of decay. Let's write it as a decimal! r=8 % ⇔ r= 0.08 We now have enough information to write the requested function.
We can find the price of the car 10 after its purchase by evaluating the function we obtained in Part A at t=10. Let's do it!
We have found that the price of the car will be about 8687.77 dollars 10 years after its purchase.