Exercise 1 Page 520

We are given a figure.

Here we want to find the distance from point $E$ to $\overleftrightarrow{FH}.$ Recall that the distance from a point to a line is defined as the shortest distance. This is going to be the segment that runs perpendicular to $\overleftrightarrow{FH}.$ Therefore, we can disregard $\overline{EF}$ and $\overline{EH}.$

To find the distance between $E$ and $\overleftrightarrow{FH},$ we have to use the Distance Formula. Let's recall the Distance Formula.

Distance Formula

Given two points $A(x_1,y_1)$ and $B(x_2,y_2)$ on a coordinate plane, their distance $d$ is given by the following formula. $$\begin{array}{c}d=\sqrt{{\left(x_2-x_1\right)}^2+{\left(y_2-y_1\right)}^2}\end{array}$$

Therefore, we will use two points $E$ and $G$ to find the distance between point $E$ and the line. We will substitute $x\text{-}$ and $y\text{-}$values of the points into the formula and simplify it. Let's do it. We found the distance between the point and the line as $\sqrt{50}.$