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First Triangle:
m∠ B≈ 52.3^(∘), m∠ C≈ 87.7^(∘), c≈ 20.2
Second Triangle:
m∠ B≈ 127.7^(∘), m∠ C≈ 12.3^(∘), c≈ 4.3
First Triangle:
m∠ B≈ 42.4^(∘), m∠ C≈ 116.6^(∘), c≈ 42.4
Second Triangle:
m∠ B≈ 137.6^(∘), m∠ C≈ 21.4^(∘), c≈ 17.3
Acute Angle:& &m∠ A= 40^(∘) Opposite Side:& &a= 13 Adjacent Side:& &b= 16 We will use the Law of Sines to solve △ ABC. This is an ambiguous case, so there are two possible solutions for △ ABC.
Let's find these solutions one at a time.
In the first case we assume that ∠ B is an acute angle.
In the second case we assume that ∠ B is an obtuse angle.
Remember that the inverse sine function gives only acute angle measures. Therefore, in this case we will find m∠ B using supplementary angles. In the first solution we have found the measure of the supplement of the current ∠ B, about 52.3^(∘).
Now we can find the measures of ∠ B and ∠ C. & m∠ B≈ 180^(∘)- 52.3^(∘)=127.7^(∘) & m∠ C≈ 180^(∘)- 40^(∘)-127.7^(∘)=12.3^(∘) Finally, let's find the value of c using the Law of Sines. 13/sin 40^(∘)≈c/sin12.3^(∘) ⇔ c≈ 4.3 The length c of the remaining side of the triangle is about 4.3 units.
Acute Angle:& &m∠ A= 21^(∘) Opposite Side:& &a= 17 Adjacent Side:& &b= 32 We will use the Law of Sines to solve △ ABC. This is an ambiguous case, so there are two possible solutions for △ ABC.
Let's find these solutions one at a time.
In the first case we assume that ∠ B is an acute angle.
In the second case we assume that ∠ B is an obtuse angle.
Remember that the inverse sine function gives only acute angle measures. Therefore, in this case we will find m∠ B using supplementary angles. In the first solution we have found the measure of the supplement of the current ∠ B, about 42.4^(∘).
Now we can find the measures of ∠ B and ∠ C. & m∠ B≈ 180^(∘)- 42.4^(∘)=137.6^(∘) & m∠ C≈ 180^(∘)- 21^(∘)-137.6^(∘)=21.4^(∘) Finally, let's find the value of c using the Law of Sines. 17/sin 21^(∘)≈c/sin21.4^(∘) ⇔ c≈ 17.3 The length c of the remaining side of the triangle is about 17.3 units.