Big Ideas Math Geometry, 2014
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Big Ideas Math Geometry, 2014 View details
7. Law of Sines and Law of Cosines
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Exercise 47 Page 515

Practice makes perfect
a We are given the measure of one acute angle of △ ABC, the length of one adjacent side, and the length of the side opposite that angle, which is less than the length of the adjacent side.

Acute Angle:& &m∠ A= 40^(∘) Opposite Side:& &a= 13 Adjacent Side:& &b= 16 We will use the Law of Sines to solve △ ABC. This is an ambiguous case, so there are two possible solutions for △ ABC.

Let's find these solutions one at a time.

Solution I

In the first case we assume that ∠ B is an acute angle.

Now we will apply the Law of Sines to the above triangle. 13/sin 40^(∘)=16/sinB=c/sinC The obtained expression can be split into two equations. 13/sin40^(∘)=16/sinB and 13/sin40^(∘)=c/sinC We will solve the first equation for the measure of ∠ B. First, let's rewrite the equation so that the sine of ∠ B is isolated on the left-hand side.
13/sin40^(∘)=16/sinB
Simplify
13sinB=16sin40^(∘)
sinB=16sin40^(∘)/13
Now we will use the inverse sine ratio. sinB=16sin40^(∘)/13 ⇕ m∠ B=sin^(- 1)(16sin40^(∘)/13) Let's approximate the value of m∠ B to the nearest tenth of a degree using a calculator. m∠ B=sin^(- 1)(16sin40^(∘)/13)≈ 52.3^(∘) The measure of ∠ B is about 52.3^(∘). We will find the measure of the third angle ∠ C using the Triangle Sum Theorem. m∠ C≈ 180^(∘)- 40^(∘)- 52.3^(∘)=87.7^(∘) The measure of ∠ C is about 87.7^(∘). Finally we will use the second equation to estimate the length c of the remaining side. 13/sin40^(∘)≈c/sin 87.7^(∘) ⇔ c≈13sin87.7^(∘)/sin40^(∘) Let's use a calculator. c≈13sin87.7^(∘)/sin40^(∘)≈ 20.2 The length c of the remaining side of the triangle is about 20.2 units.

Solution II

In the second case we assume that ∠ B is an obtuse angle.

Remember that the inverse sine function gives only acute angle measures. Therefore, in this case we will find m∠ B using supplementary angles. In the first solution we have found the measure of the supplement of the current ∠ B, about 52.3^(∘).

Now we can find the measures of ∠ B and ∠ C. & m∠ B≈ 180^(∘)- 52.3^(∘)=127.7^(∘) & m∠ C≈ 180^(∘)- 40^(∘)-127.7^(∘)=12.3^(∘) Finally, let's find the value of c using the Law of Sines. 13/sin 40^(∘)≈c/sin12.3^(∘) ⇔ c≈ 4.3 The length c of the remaining side of the triangle is about 4.3 units.

b We are given the measure of one acute angle of △ ABC, the length of one adjacent side, and the length of the side opposite that angle, which is less than the length of the adjacent side.

Acute Angle:& &m∠ A= 21^(∘) Opposite Side:& &a= 17 Adjacent Side:& &b= 32 We will use the Law of Sines to solve △ ABC. This is an ambiguous case, so there are two possible solutions for △ ABC.

Let's find these solutions one at a time.

Solution I

In the first case we assume that ∠ B is an acute angle.

Now we will apply the Law of Sines to the above triangle. 17/sin 21^(∘)=32/sinB=c/sinC The obtained expression can be split into two equations. 17/sin21^(∘)=32/sinB and 17/sin21^(∘)=c/sinC We will solve the first equation for the measure of ∠ B. First, let's rewrite the equation so that the sine of ∠ B is isolated on the left-hand side.
17/sin21^(∘)=32/sinB
Simplify
17sinB=32sin21^(∘)
sinB=32sin21^(∘)/17
Now we will use the inverse sine ratio. sinB=32sin21^(∘)/17 ⇕ m∠ B=sin^(- 1)(32sin21^(∘)/17) Let's approximate the value of m∠ B to the nearest tenth of a degree using a calculator. m∠ B=sin^(- 1)(32sin21^(∘)/17)≈ 42.4^(∘) The measure of ∠ B is about 42.4^(∘). We will find the measure of the third angle ∠ C using the Triangle Sum Theorem. m∠ C≈ 180^(∘)- 21^(∘)- 42.4^(∘)=116.6^(∘) The measure of ∠ C is about 116.6^(∘). Finally we will use the second equation to estimate the length c of the remaining side. 17/sin21^(∘)≈c/sin 116.6^(∘) [0.7em] ⇕ [0.7em] c≈17sin116.6^(∘)/sin21^(∘) Let's use a calculator. c≈17sin116.6^(∘)/sin21^(∘)≈ 42.4 The length c of the remaining side of the triangle is about 42.4 units.

Solution II

In the second case we assume that ∠ B is an obtuse angle.

Remember that the inverse sine function gives only acute angle measures. Therefore, in this case we will find m∠ B using supplementary angles. In the first solution we have found the measure of the supplement of the current ∠ B, about 42.4^(∘).

Now we can find the measures of ∠ B and ∠ C. & m∠ B≈ 180^(∘)- 42.4^(∘)=137.6^(∘) & m∠ C≈ 180^(∘)- 21^(∘)-137.6^(∘)=21.4^(∘) Finally, let's find the value of c using the Law of Sines. 17/sin 21^(∘)≈c/sin21.4^(∘) ⇔ c≈ 17.3 The length c of the remaining side of the triangle is about 17.3 units.