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Law of Sines |
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For any triangle, the ratio between the length of the side and the sine value of its opposite angle is constant. |
Before we use the law, let's label the vertices of the triangle. We will use the diagram from Part A.
Now we will apply the Law of Sines to the triangle.
a/sinA=62/sin58^(∘)=54/sinC
Cross multiply
.LHS /62.=.RHS /62.
To find the measure of ∠C, let's use the inverse sine ratio. sinC=54sin58^(∘)/62 ⇕ m∠C=sin^(- 1)(54sin58^(∘)/62) We will use a calculator to approximate m∠C to the nearest tenth of a degree. m∠C=sin^(- 1)(54sin58^(∘)/62)≈ 47.6^(∘) We have that the measure of ∠C is about 47.6^(∘).
To find the measure of the remaining angle ∠A, we will use the Triangle Sum Theorem. m∠A≈ 180^(∘)- 58^(∘)- 47.6^(∘)=74.4^(∘) The measure of ∠A is about 74.4^(∘). We will substitute 74.4^(∘) for A in the first equation and solve it for a. a/sin 74.4^(∘)≈62/sin58^(∘) ⇔ a≈62sin74.4^(∘)/sin58^(∘) Finally, let's use a calculator. a≈62sin74.4^(∘)/sin58^(∘)≈ 70.4 The length of the third side of the triangle is about 70.4 feet.
Recall that the area of any triangle is given by one-half the product of the lengths of two sides times the sine of their included angle. In Part B, we found that the included angle of the 62-foot side and the 54-foot side is about 74.4^(∘).
Multiply
1/b* a = a/b
Use a calculator
The area of the garden is about 1612.3 square feet. One bag of fertilizer covers an area of 200 square feet. Let's calculate the number of bags needed to fertilize the entire garden. 1612.3/200=8.0615 Since you cannot purchase a part of a bag, you will need 9 bags of fertilizer for the garden.