Big Ideas Math Geometry, 2014
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Big Ideas Math Geometry, 2014 View details
7. Law of Sines and Law of Cosines
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Exercise 30 Page 514

Note that △ ABC is a right triangle.

Which Law or Theorem Would You Use? Pythagorean Theorem
Why? Triangle △ ABC is a right triangle.
Remaining Side and Angles: b≈ 16.2, m∠ A≈ 67.8^(∘), m∠ C≈ 22.2^(∘)

Practice makes perfect

Let's start by sketching △ ABC and labeling sides a, c, and angle ∠ B. Remember that m∠ B= 90^(∘), a= 15, and c= 6.

We will solve △ ABC. This means we will find the values of b, m∠ A, and m∠ C. First, let's find the length of the remaining side and then let's move on to the measures of the remaining angles.

Remaining Side

Since m∠ B=90^(∘), △ ABC is a right triangle. We are given the lengths of two sides of the triangle, so we can use the Pythagorean Theorem to find the length b of the third side. Let's recall the theorem.

Pythagorean Theorem

In a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the legs.

In our case the length of the hypotenuse is b, and the lengths of the legs are a= 15 and c= 6. Let's apply the Pythagorean Theorem to our triangle. 15^2+ 6^2=b^2 Finally we will solve the obtained equation for b.
15^2+6^2=b^2
Solve for b
b^2=15^2+6^2
b^2=225+36
b^2=261
b=sqrt(261)
b≈ 16.2
The length b of the third side of the triangle is about 16.2 units. Let's update our diagram.

Remaining Angles

Next we will find the measures of the two remaining angles. Let's start with m∠ A. Since now we know the lengths of all three sides of △ ABC and the measure of one angle, we can use the Law of Sines.

Law of Sines

For any triangle the ratio between the sine value of an angle and the length of its opposite side is constant.

Let's apply the Law of Sines to △ ABC. sinA/15=sin 90^(∘)/16.2=sinC/6 Now we will write an equation involving the sine of ∠ A. sinA/15=sin90^(∘)/16.2 ⇔ sinA=15sin90^(∘)/16.2 To find the measure of ∠ A, let's use the inverse sine ratio. sinA=15sin90^(∘)/16.2 ⇕ m∠ A=sin^(- 1)(15sin90^(∘)/16.2) We will use a calculator to approximate m∠ A to the nearest tenth of a degree. m∠ A=sin^(- 1)(15sin90^(∘)/16.2)≈ 67.8^(∘) To find the measure of ∠ C, we could solve an equation involving the sine of ∠ C, or we can use the Triangle Sum Theorem. m∠ C≈ 180^(∘)-67.8^(∘)- 90^(∘)=22.2^(∘) The value of m∠ C is about 22.2^(∘).