Sign In
Note that △ ABC is a right triangle.
Which Law or Theorem Would You Use? Pythagorean Theorem
Why? Triangle △ ABC is a right triangle.
Remaining Side and Angles: b≈ 16.2, m∠ A≈ 67.8^(∘), m∠ C≈ 22.2^(∘)
Let's start by sketching △ ABC and labeling sides a, c, and angle ∠ B. Remember that m∠ B= 90^(∘), a= 15, and c= 6.
We will solve △ ABC. This means we will find the values of b, m∠ A, and m∠ C. First, let's find the length of the remaining side and then let's move on to the measures of the remaining angles.
Since m∠ B=90^(∘), △ ABC is a right triangle. We are given the lengths of two sides of the triangle, so we can use the Pythagorean Theorem to find the length b of the third side. Let's recall the theorem.
Pythagorean Theorem |
In a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the legs. |
Rearrange equation
Calculate power
Add terms
sqrt(LHS)=sqrt(RHS)
Use a calculator
Next we will find the measures of the two remaining angles. Let's start with m∠ A. Since now we know the lengths of all three sides of △ ABC and the measure of one angle, we can use the Law of Sines.
Law of Sines |
For any triangle the ratio between the sine value of an angle and the length of its opposite side is constant. |
Let's apply the Law of Sines to △ ABC. sinA/15=sin 90^(∘)/16.2=sinC/6 Now we will write an equation involving the sine of ∠ A. sinA/15=sin90^(∘)/16.2 ⇔ sinA=15sin90^(∘)/16.2 To find the measure of ∠ A, let's use the inverse sine ratio. sinA=15sin90^(∘)/16.2 ⇕ m∠ A=sin^(- 1)(15sin90^(∘)/16.2) We will use a calculator to approximate m∠ A to the nearest tenth of a degree. m∠ A=sin^(- 1)(15sin90^(∘)/16.2)≈ 67.8^(∘) To find the measure of ∠ C, we could solve an equation involving the sine of ∠ C, or we can use the Triangle Sum Theorem. m∠ C≈ 180^(∘)-67.8^(∘)- 90^(∘)=22.2^(∘) The value of m∠ C is about 22.2^(∘).