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Is there a greatest common factor between all of the terms in the given expression? If so, you should factor that out first.
4(x-5)(x+4)
Let's start factoring by first identifying the greatest common factor (GCF). Then, we will rewrite the expression as a trinomial with a leading coefficient of 1.
4( x^2-x-20) Let's temporarily only focus on this trinomial, and we will bring back the GCF after factoring.
To factor a trinomial with a leading coefficient of 1, think of the process as multiplying two binomials in reverse. Let's start by taking a look at the constant term. x^2-x - 20 In this case, we have - 20. This is a negative number, so for the product of the constant terms in the factors to be negative, these constants must have the opposite sign (one positive and one negative.)
Factor Constants | Product of Constants |
---|---|
1 and - 20 | - 20 |
2 and - 10 | - 20 |
4 and - 5 | - 20 |
5 and - 4 | - 20 |
10 and - 2 | - 20 |
20 and - 1 | - 20 |
Next, let's consider the coefficient of the linear term. x^2 - 1 x - 20 For this term, we need the sum of the factors that produced the constant term to equal the coefficient of the linear term, - 1.
Factors | Sum of Factors |
---|---|
1 and - 20 | - 19 |
2 and - 10 | - 8 |
4 and - 5 | - 1 |
5 and - 4 | 1 |
10 and - 2 | 8 |
20 and - 1 | 19 |
We found the factors whose product is - 20 and whose sum is - 1. x^2 - 1x - 20 ⇔ (x-5)(x+4) Wait! Before we finish, remember that we factored out a GCF from the original expression. To fully complete the factored expression, let's reintroduce that GCF now.
4(x-5)(x+4)