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Is there a greatest common factor between all of the terms in the given expression? If so, you should factor that out first.
4(x-5)(x+4)
Let's start factoring by first identifying the greatest common factor (GCF). Then, we will rewrite the expression as a trinomial with a leading coefficient of 1.
The GCF of an expression is a common factor of the terms in the expression. It is the common factor with the greatest coefficient and the greatest exponent. In this case, the GCF is 4.
The result of factoring out a GCF from the given expression is a trinomial with a leading coefficient of 1.
To factor a trinomial with a leading coefficient of 1, think of the process as multiplying two binomials in reverse. Let's start by taking a look at the constant term. x^2-x - 20 In this case, we have - 20. This is a negative number, so for the product of the constant terms in the factors to be negative, these constants must have the opposite sign (one positive and one negative.)
| Factor Constants | Product of Constants |
|---|---|
| 1 and - 20 | - 20 |
| 2 and - 10 | - 20 |
| 4 and - 5 | - 20 |
| 5 and - 4 | - 20 |
| 10 and - 2 | - 20 |
| 20 and - 1 | - 20 |
Next, let's consider the coefficient of the linear term. x^2 - 1 x - 20 For this term, we need the sum of the factors that produced the constant term to equal the coefficient of the linear term, - 1.
| Factors | Sum of Factors |
|---|---|
| 1 and - 20 | - 19 |
| 2 and - 10 | - 8 |
| 4 and - 5 | - 1 |
| 5 and - 4 | 1 |
| 10 and - 2 | 8 |
| 20 and - 1 | 19 |
We found the factors whose product is - 20 and whose sum is - 1.
x^2 - 1x - 20 ⇔ (x-5)(x+4)
Wait! Before we finish, remember that we factored out a GCF from the original expression. To fully complete the factored expression, let's reintroduce that GCF now.
4(x-5)(x+4)
Distribute 4
Distribute (x+4)
Distribute 4x
Distribute - 20
Subtract term
After applying the Distributive Property and simplifying, the result is the same as the given expression. Therefore, we can be sure our solution is correct!