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Begin by writing an equation that represents the average monthly cost of the Internet service provider. Let y be the average monthly cost and x be the number of months of service.
The competitor is a better choice for less than 18 months of service. See solution.
We will begin by writing an equation that represents the average monthly cost of the Internet service provider. Let y be the average monthly cost and x be the number of months of service.
| Verbal Expression | Algebraic Expression |
|---|---|
| Installation fee ($) | 50 |
| Fee for x months ($) | 43 x |
| Total fee ($) | 43 x+ 50 |
| Average monthly cost is $y. | y=43 x+ 50/x |
We now have the equation.
x= 6
Multiply
Add terms
.LHS /6.=.RHS /6.
Round to 2 decimal place(s)
The average monthly cost is about $51.33 for 6 months of service. Proceeding in the same way, we can find the average cost for 12, 18, and 24 months of service.
| Months, x | 43x+50/x | Average monthly cost of the Internet service provider (dollars), y | Average monthly cost of the competitor (dollars), y |
|---|---|---|---|
| 6 | 43( 6)+50/6 | $51.33 | $49.83 |
| 12 | 43( 12)+50/12 | $47.17 | $46.92 |
| 18 | 43( 18)+50/18 | $45.78 | $45.94 |
| 24 | 43( 24)+50/24 | $45.08 | $45.45 |
Interpreting the table, we can say that the competitor is a better choice for less than 18 months of service.