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Solving Radical Equations
Choose Course
Algebra 2
Radical Functions
Solving Radical Equations
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Solving Radical Equations 1.8 - Solution
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Return to Solving Radical Equations
Solving a
radical equation
usually involves three main steps.
Isolate the radical on one side of the equation.
Raise each side of the equation to a power equal to the index of the radical to eliminate the radical.
Solve the resulting equation.
Check the results for
extraneous solutions
.
Now we can analyze the given radical equation.
x
+
1
3
−
8
=
-
2
First, let's isolate the radical,
x
+
1
3
,
on one side of the equation.
x
+
1
3
−
8
=
-
2
AddEqn
LHS
+
8
=
RHS
+
8
x
+
1
3
=
6
We get an isolated radical with index equal to
2
.
Then, we will raise each side of the equation to the power of
2
.
x
+
1
3
=
6
RaiseEqn
LHS
2
=
RHS
2
(
x
+
1
3
)
2
=
6
2
Solve for
x
PowSqrt
(
a
)
2
=
a
x
+
1
3
=
6
2
CalcPow
Calculate power
x
+
1
3
=
3
6
SubEqn
LHS
−
1
3
=
RHS
−
1
3
x
=
2
3
Next, we will check for extraneous solutions. We do that by substituting
2
3
for
x
into the original equation. If the substitution produces a true statement, we know that our answer is correct. If it does not, then it is an extraneous solution.
x
+
1
3
−
8
=
-
2
Substitute
x
=
2
3
2
3
+
1
3
−
8
=
?
-
2
Simplify
AddTerms
Add terms
3
6
−
8
=
?
-
2
CalcRoot
Calculate root
6
−
8
=
?
-
2
SubTerms
Subtract terms
-
2
=
-
2
✓
Because our substitution produced a true statement, we know that our answer,
x
=
2
3
,
is correct.