Now we can analyze the given radical equation.
3x−16=2
We obtained an isolated radical with index equal to 3. Then, we will raise each side of the equation to the power of 3.
Next, we will check for extraneous solutions. We do that by substituting 24 for x into the original equation. If the substitution produces a true statement, we know that our answer is correct. If it does not, then it is an extraneous solution.