Let's begin by determining the degree of each function. It is determined by the exponent with the highest value. The polynomial function p(x)=0.6x3+2x2+4 is of degree 3, q(x)=x+4 is of degree 1 and h(x)=0.2x2+x+4 is of degree 2. Now we need to link each graph to its corresponding function by thinking about what the functions' graphs should look in order for them to match.
Graph A has the following end behavior. As x→-∞,f(x)→-∞andAs x→+∞,f(x)→∞ That is consistent with a function with odd degree. We have two polynomial functions with odd degree, p(x) and q(x). Since the graph is not a linear function, then q(x) is not a match. Therefore, we know that the graph must be that of the function p(x)=0.6x3+2x2+4.
Now there are two functions left, h(x) and q(x). Since the graph B is a parabola, the function has a degree of 2. Therefore, the function h(x)=0.2x2+x+4 is the function for this graph.
Since the blue graph is a line it represents a linear function. Thus, we can conclude that it is the graph of q(x)=x+4.