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| 12 Theory slides |
| 12 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
Try your knowledge on these topics.
Round the answer to the closest integer.
In 2007, a satellite named SELENE was launched to explore the Moon's surface for a few years. It orbited the Moon in a circular path staying at a constant altitude of 100 kilometers. Given that the radius of the Moon is 1737 kilometers, find the distance that the satellite traveled when it completed 60% of its orbit.
In order to introduce the concept of radian measure, the definition of a radian should first be explored.
radis seldom written. Instead, no unit marker indicates radians. Consider two expressions.
Degrees to Radians | Radians to Degrees |
---|---|
1∘=180π rad | 1 rad=π180∘ |
LHS/π=RHS/π
Calculate quotient
Rearrange equation
To understand the observed relation, consider two concentric circles with different radii r1 and r2.
LHS⋅r2s2=RHS⋅r2s2
Cancel out common factors
Simplify quotient and product
LHS/r1=RHS/r1
ca⋅b=ca⋅b
LHS/r2=RHS/r2
The radian measure of a central angle is defined as the quotient between the length of the arc intercepted by the angle and the radius of the circle.
Based on the diagram above, the radian measure of the central angle ∠O is defined as follows.
θ=rs
By using this definition, the formula for the length of an arc can be derived.
s=θr
s=2πr(360∘θ)
This equivalent form is convenient to work with because 2πr is the circumference of a circle. Since a full circle measures 360∘, dividing 2πr by 360 results in the length of an arc intercepted by a 1-degree central angle. Finally, by multiplying that value by the measure of the arc, its length is obtained.
In her room Paulina has a big clock whose longer hand is 9 centimeters long. When Paulina came home and looked at her clock, it was exactly 2 P.M. She calculated the angle between the longer and shorter hands of the clock to be 60∘.
Since the central angle is given in degrees, the arc length can be calculated using the formula s=2πr(360∘θ).
r=15, θ=60∘
ba=b/60∘a/60∘
a⋅b1=ba
Multiply
ba=b/3a/3
Use a calculator
Round to 1 decimal place(s)
After having dinner, Paulina decided to do her math homework. She is given a circle with radius 5 inches and an inscribed angle that measures 40∘.
To convert the measure of an angle from degrees to radians, use the conversion factor 180∘π. The length of the arc can be found by using the formula s=θr, where θ is the measure of the corresponding central angle in radians.
m∠MKN=92π
LHS⋅2=RHS⋅2
ca⋅b=ca⋅b
Multiply
Rearrange equation
m∠MON=94π, r=5
ca⋅b=ca⋅b
Multiply
Use a calculator
Round to nearest integer
Finally, Paulina finished all her homework. She could now go to an amusement park with her friends. They get on a Ferris Wheel feeling super excited. The diagram indicates their positions.
Identify the type of each angle. Use the formula for the arc length.
It is given that the length of an arc between each cabin is 3 meters. There is one cabin between Paulina and Tiffaniqua, so the arc between their cabins is 6 meters long.
s=6, r=12
Multiply
a⋅cb=ca⋅b
ba=b/24a/24
LHS⋅15∘=RHS⋅15∘
Rearrange equation
LHS/π=RHS/π
Use a calculator
Round to 1 decimal place(s)
The challenge presented at the beginning of this lesson can now be solved thanks to the concepts covered.
In 2007, a satellite named SELENE was launched to explore the Moon's surface for a few years. It orbited the Moon in a circular path staying at a constant altitude of 100 kilometers. Given that the radius of the Moon is 1737 kilometers, find the distance that the satellite traveled when it completed 60% of its orbit.θ=1.2π, r=1837
Use a calculator
Round to nearest integer
Let's start by drawing the unit circle and mark the shortest arc that is created by P and Q on the circle's circumference.
To determine the length of this arc, we will use the following formula. s = θ r In this formula, θ is the measure of the central angle in radians. Since the unit circle has a radius of r= 1, the length of the arc is the same as the central angle. s = θ ( 1) ⇔ s = θ We can calculate θ by subtracting θ_Q from θ_P.
Remember that the x-coordinate of a point on the unit circle is the cosine of the central angle. Therefore, P has a cosine value of 0.1 and Q has a cosine value of 0.6. That allows us to write two equations. cos θ_P &= 0.1 ⇔ θ_P = cos^(-1) 0.1 cos θ_Q &= 0.6 ⇔ θ_Q = cos^(-1) 0.6 Let's substitute these identities in the equation describing θ.
To calculate this we need a graphing calculator. Before we can calculate it though, we must make sure the calculator interprets the argument of trigonometric functions as radians. Push MODE and select Radian
on the third row.
Now, we can continue calculating the measure of θ.
Five congruent circles are placed next to each other such that their radii form a regular pentagon when connected.
Since we are not given any lengths, we must find expressions which can be compared. Notice that we are comparing a sum of circle radii to the length of the arcs. These can be compared, even without actual lengths, if we work in radians.
Let's label the radius of each circles a.
As we can see, the perimeter of the pentagon equals the sum of two radii for each of the five circles. With this information, we can determine an expression for the perimeter. 5( 2a) = 10 a
To calculate the length of the arcs, we need to find the sum of the angle measures of a pentagon. (n-2)* 180^(∘) ⇓ (5-2)* 180^(∘)=540^(∘) The measures of the interior angles sum to 540^(∘). Since the pentagon is regular, each angle has a measure of one fifth of this. 540^(∘)/5=108^(∘) Let's rewrite this from degrees to radians.
Each angle has a measure of 3π5 radians. Notice that each of these angles also is a central angle in a circle.
When we know the measure of each central angle, we can find the arc length using the following formula. s = θ r In this formula, θ is the measure of the central angle in radians.
The length of one arc is 3aπ5. If we multiply this by 5 we get the combined length of the five arcs. 5s = 5(3aπ/5) ⇓ 5s ≈ 9.424a Since 9.424a<10a, we know that the sum of the arc lengths is less than the perimeter of the pentagon.
Here, we are now dealing with a polygon formed by six rather than five circles. Since the polygon will then have six sides, it is a regular hexagon. Let's draw the figure to aid our solving process.
Again, if we label the radius of each circle as a, we get a total perimeter of 6 times 2a. Perimeter of Hexagon: 6(2a)=12a Now we want to calculate the length of the arcs. A hexagon has a total angle sum of 720^(∘) and each of the six angles measures 120^(∘). Let's rewrite this as radians.
Each angle has a measure of 2π3 radians.
Let's calculate the length of one arc and then multiply this by 6 to account for all of the arcs.
Since 12.57a>12a, we know that the sum of the arc lengths is greater than the perimeter of the hexagon.