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Recall the classification of quadrilaterals. You can begin by finding the slopes of the sides.
Isosceles trapezoid
Let's plot the given points on a coordinate plane and graph the quadrilateral.
Let's now determine the most precise name for our quadrilateral.
To determine the most precise name for our quadrilateral, let's review the classification of quadrilaterals.
| Quadrilateral | Definition |
|---|---|
| Parallelogram | Both pairs of opposite sides are parallel |
| Rhombus | Parallelogram with four congruent sides |
| Rectangle | Parallelogram with four right angles |
| Square | Parallelogram with four congruent sides and four right angles |
| Trapezoid | Quadrilateral with exactly one pair of parallel sides |
| Isosceles Trapezoid | Trapezoid with legs that are congruent |
| Kite | Quadrilateral with two pairs of consecutive sides congruent and no opposite sides congruent |
Now, let's find the slopes of the sides using the Slope Formula.
| Side | Slope Formula | Simplified |
|---|---|---|
| Slope of $\Seg{HA}\text{:}$ $(\col{\N 9,10}),$ $(\colIII{2,10})$ | $\dfrac{\colIII{10}-\col{10}}{\colIII{2}-(\col{\N 9})}$ | $0$ |
| Slope of $\Seg{AT}\text{:}$ $(\colIII{2,10}),$ $(\colIV{4, 4})$ | $\dfrac{\colIV{4}-\colIII{10}}{\colIV{4}-\colIII{2}}$ | $\N 3$ |
| Slope of $\Seg{TW}\text{:}$ $(\colIV{4, 4}),$ $(\colVI{\N 11, 4})$ | $\dfrac{\colVI{4}-\colIV{4}}{\colVI{\N11}-\colIV{4}}$ | $0$ |
| Slope of $\Seg{WH}\text{:}$ $(\colVI{\N 11, 4}),$ $(\col{\N 9,10})$ | $\dfrac{\col{10}-\colVI{4}}{\col{\N 9}-(\colVI{\N 11})}$ | $3$ |
We can tell that the quadrilateral has exactly one pair of parallel sides. Therefore, it is either a trapezoid or an isosceles trapezoid. To check, we can find the lengths of the legs of the trapezoid using the Distance Formula.
| Side | Distance Formula | Simplified |
|---|---|---|
| Length of $\Seg{AT}\text{:}$ $(\colIII{2,10}),$ $(\colIV{4, 4})$ | $\sqrt{(\colIV{4}-\colIII{2})^2+(\colIV{4}-\colIII{10})^2}$ | $\sqrt{40}$ |
| Length of $\Seg{WH}\text{:}$ $(\colVI{\N 11, 4}),$ $(\col{\N 9,10})$ | $\sqrt{(\col{\N 9}-(\colVI{\N 11}))^2+(\col{10}-\colVI{4})^2}$ | $\sqrt{40}$ |
The legs of our trapezoid are congruent. Therefore, the most precise name for this quadrilateral is an isosceles trapezoid.