Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
3. Surface Areas of Pyramids and Cones
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Exercise 10 Page 713

Use the formula for the surface area of a pyramid.

138m^2

Practice makes perfect

We want to find the surface area of the given pyramid.

To calculate the surface area of a pyramid, we can use the formula where p is the perimeter of the base, l is the slant height of the pyramid, and B is the area of the base. S.A.=1/2pl+B The base of the pyramid is a regular polygon consisting of six sides that are each 4m long. Let's calculate its perimeter! p=6s ⇒ p=6( 4)=24m The area of a regular hexagon equals to the half of the apothem of the hexagon multiplied by its perimeter. We are given that the apothem is 2sqrt(3)m. Let's calculate the area of the base! B=1/2ap ⇒ B=1/2( 2sqrt(3))(24)=24sqrt(3)m^2 We are also given that the slant height l is 8m. Let's substitute all of these values into the formula for the surface area and calculate it.
S.A.=1/2pl+B
S.A.=1/2(24)(8)+24sqrt(3)
Simplify right-hand side
S.A.=192/2+24sqrt(3)
S.A.=96+24sqrt(3)
S.A.=96+41.569219...
S.A.=137.569219...
S.A.≈ 138
The surface area of the pyramid is about 138 square meters.