Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
3. Surface Areas of Pyramids and Cones
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Exercise 18 Page 713

The lateral area of a right cone is half the product of the circumference of the base and the slant height.

47cm^2

Practice makes perfect

We want to find the lateral area of the given cone.

We know that the lateral area of a right cone is half the product of the circumference of the base and the slant height of the cone. L.A.=1/2* 2π r* l ⇔ L.A.=π rl In this formula, r is the radius and l is the slant height of the cone. Although we do not have the slant height, we can find it by using the Pythagorean Theorem. We have that radius of the base is 3 centimeters.

In this right triangle, the legs are 3 and 4 centimeters long. The hypotenuse is l. We will substitute these values in the Pythagorean Theorem and solve for l.
a^2+b^2=c^2
3^2+ 4^2= l^2
Solve for l
9+16=l ^2
25=l ^2
5=l
l=5
The hypotenuse of the right triangle, and therefore the slant height of the cone, is 5 centimeters long.
With this information, we are able to calculate the lateral area of the cone. Substitute r=3 and l=5 into the formula for the lateral area. Let's do it!
L.A.=π rl
L.A.=π ( 3)( 5)
L.A.=47.123889...
L.A.≈ 47
The lateral area of the given cone is about 47 square centimeters.