Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
3. Surface Areas of Pyramids and Cones
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Exercise 39 Page 714

Revolving a point about a line will get us a circle.

Solid: A composite solid made by subtracting a cone from a cylinder. The radius of the cylinder is 4 units and the height is 3 units.
Surface Area: 60Ď€ square units

Practice makes perfect

Let's take a look at the given triangle.

We will revolve the given triangle about the line x=4. Remember that revolving a point about the line will get us a circle.

We see that the revolved triangle is a composite solid made by subtracting a cone from a cylinder. The radius of the cylinder is 4 units and the height is 3 units. We are asked to find the surface area of the revolved solid. First, let's find the slant height of the cone, l.

We will find l using the Pythagorean Theorem for the right triangle.
r^2+ h^2= l^2
4^2+ 3^2= l^2
â–Ľ
Solve for l
16+9= l^2
25= l^2
l^2=25
l=sqrt(25)
l=5
The surface area of the composite solid consists of three parts.
  • The lateral area of the cone, L.A._(cone).
  • The lateral area of the cylinder, \text{L.A.}_\text{cyl}.
  • The base area of the cylinder, B.

Let's find them!

Radius r= 4
Height h= 3
Slant Height l= 5
\text{L.A.}_\text{cone} π r l=π ( 4)( 5)=20π
\text{L.A.}_\text{col} 2Ď€ r h=2Ď€ ( 4)( 3)=24Ď€
B π r^2=π ( 4)^2=16π

Finally we will find the surface area of the composite solid, S.A.. \begin{gathered} \textcolor{darkviolet}{\text{S.A.}}=\text{L.A.}_\text{cone}+\text{L.A.}_\text{col}+B \\ \Downarrow \\ \textcolor{darkviolet}{\text{S.A.}}=\textcolor{darkorange}{20\pi}+\textcolor{darkorange}{24\pi}+\textcolor{darkorange}{16\pi}=\textcolor{darkviolet}{60\pi} \end{gathered} The surface area of the revolved solid is 60Ď€ square units.