Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
3. Surface Areas of Pyramids and Cones
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Exercise 17 Page 713

The lateral area of a right cone is half the product of the circumference of the base and the slant height.

31m^2

Practice makes perfect

We want to find the lateral area of the given cone.

We know that the lateral area of a right cone is half the product of the circumference of the base and the slant height. L.A.=1/2* 2π r* l ⇔ L.A.=π rl In this formula, r is the radius and l is the slant height of the cone. Although we do not have the slant height, we can find it by using the Pythagorean Theorem. Since the diameter of the base is 4 meters, we have that its radius is 4÷ 2=2 meters.

In this right triangle, the legs are 4.5 and 2 meters long. The hypotenuse is l. We will substitute these values in the Pythagorean Theorem and solve for l.
a^2+b^2=c^2
4.5^2+ 2^2= l^2
Solve for l
20.25+4=l ^2
24.25=l ^2
sqrt(24.25)=l
l=sqrt(24.25)
The hypotenuse of the right triangle, and therefore the slant height of the cone, is sqrt(24.25) meters long.
With this information we are able to calculate the lateral area of the cone. Substitute r=2 and l=sqrt(24.25) into the formula for the lateral area. Let's do it!
L.A.=π rl
L.A.=π ( 2)( sqrt(24.25))
L.A.=30.941099...
L.A.≈ 31
The lateral area of the given cone is about 31 square meters.