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Recall the classification of quadrilaterals. You can begin by finding the slopes of the sides.
15 units squared
Let's identify the coordinates of the given quadrilateral.
First, we need to determine the most precise name for our quadrilateral. Then we can find its area.
Quadrilateral | Definition |
---|---|
Parallelogram | Both pairs of opposite sides are parallel |
Rhombus | Parallelogram with four congruent sides |
Rectangle | Parallelogram with four right angles |
Square | Parallelogram with four congruent sides and four right angles |
Trapezoid | Quadrilateral with exactly one pair of parallel sides |
Isosceles Trapezoid | Trapezoid with legs that are congruent |
Kite | Quadrilateral with two pairs of consecutive sides congruent and no opposite sides congruent |
Now, let's find the slopes of the sides using the Slope Formula.
Side | Slope Formula | Simplified |
---|---|---|
Slope of QR: ( 0,3), ( 5,5) | 5- 3/5- 0 | 2/5 |
Slope of RS: ( 5,5), (3,0) | - 5/3- 5 | 5/2 |
Slope of ST: (3,0), (0, 0) | -/-3 | 0 |
Slope of TQ: (0, 0), ( 0,3) | 3-/0- | Undefined |
We have found that the quadrilateral has no parallel sides. Therefore, we need to continue by finding the lengths of its sides. For that we will use the Distance Formula.
Side | Distance Formula | Simplified |
---|---|---|
Length of QR: ( 0,3), ( 5,5) | sqrt(( 5- 0)^2+( 5- 3)^2) | sqrt(29) |
Length of RS: ( 5,5), ( 3,0) | sqrt(( 3- 5)^2+( 0- 5)^2) | sqrt(29) |
Length of ST: ( 3,0), ( 0, 0) | sqrt(( 0- 3)^2+( 0- 0)^2) | 3 |
Length of TQ: ( 0, 0), ( 0,3) | sqrt(( 0- 0)^2+( 3- 0)^2) | 3 |
Our parallelogram has two pairs of consecutive sides congruent and no opposite sides congruent. Therefore, the most precise name for this quadrilateral is a kite.
To find the area, we can use the formula for the area of a kite. A=1/2d_1d_2 In this case we need to find the length of the diagonals, d_1=QS and d_2=RT.
Side | Distance Formula | Simplified |
---|---|---|
Length of QS: ( 0,3), ( 3,0) | sqrt(( 3- 0)^2+( 0- 3)^2) | sqrt(18) |
Length of RT: ( 5,5), ( 0, 0) | sqrt(( 0- 5)^2+( 0- 5)^2) | sqrt(50) |
Let's substitute these values into the formula to find A. A= 1/2(sqrt(18))(sqrt(50)) ⇔ A=15 The area of our kite is 15 units squared.